Spur Gears(2)
An involute of a circle is defined in a plane curve generated by a point on a tangent which rolls on the circle without slipping also by a point on a taut string which in unwrapped from a reel.When the power is being transmitted then the maximum tooth pressure is exerted along the common normal through pitch point. This force resolved into tangential and radial or normal components. These components act along and at right angles to common tangent to pitch circles.The length of path of contact is the length of common normal cutoff by the addendum circles of the wheel and pinion. So length of path of contact is KL which is the sum of the parts of the path of contacts KP and PL. The part of path of contact KP is known path of approach and part of the path of contact PL is known as path of recess.
Summary
An involute of a circle is defined in a plane curve generated by a point on a tangent which rolls on the circle without slipping also by a point on a taut string which in unwrapped from a reel.When the power is being transmitted then the maximum tooth pressure is exerted along the common normal through pitch point. This force resolved into tangential and radial or normal components. These components act along and at right angles to common tangent to pitch circles.The length of path of contact is the length of common normal cutoff by the addendum circles of the wheel and pinion. So length of path of contact is KL which is the sum of the parts of the path of contacts KP and PL. The part of path of contact KP is known path of approach and part of the path of contact PL is known as path of recess.
Things to Remember
For involute teeth
- Tangential force, FT = F cos φ and
- Radial or normal force, FR = F sin φ.
- ∴ Torque exerted on the gear shaft = FT × r
Where r is pitch circle radius of the gear.
The tangential force provides the driving torque and the radial or normal force produces radial deflection of rim and bending of shafts.
- Length of the part of the path of contact, or the path of approach,
\[KP = KN - PN = \sqrt {{{\left( {{R_A}} \right)}^2} - {{\left( {R\cos \varphi } \right)}^2}} - R\sin \varphi \]
Similarly from right angled triangle O1ML,
\[ML = \sqrt {{{\left( {{O_1}L} \right)}^2} - {{\left( {{O_1}M} \right)}^2}} = {\sqrt {{{\left( {{r_A}} \right)}^2} - {{\left( {r\cos \varphi } \right)}^2}} ^{}}\]
And MP = O1Psin φ = rsin φ
- ∴ Length of the part of the path of contact, or path of recess,
\[PL = ML - MP = \sqrt {{{\left( {{r_A}} \right)}^2} - {{\left( {r\cos \varphi } \right)}^2}} - r\sin \varphi \]
- ∴ Length of the path of contact,
\[{\rm K}L = KP + PL = \sqrt {{{\left( {{R_A}} \right)}^2} - {{\left( {R\cos \varphi } \right)}^2}} + \sqrt {{{\left( {{r_A}} \right)}^2} - {{\left( {r\cos \varphi } \right)}^2}} - \left( {R + r} \right)\sin \varphi \]
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Spur Gears(2)
Involute Teeth
An involute of a circle is defined in a plane curve generated by a point on a tangent which rolls on the circle without slipping also by a point on a taut string which in unwrapped from a reel as shown in fig. In connection with the toothed wheels then the circle is known as base circle. The involute is traced as follows.
Fig: Construction of involute curve
Let A be the starting point of involute. The base circle is now divided into the equal number of parts e.g. AP1, P1P2, P2P3 etc. The tangents at the P1, P2, P3 etc. are drawn and length P1A1, P2A2, P3A3 equal to the arcs AP1, AP2 and AP3 are set off. Joining the points like A, A1, A2, A3. We obtain involute curve AR. A little supposition show that at any instant A3 the tangent A3T to involute is normal to P3A3 and P3A3 is the normal to the involute. Normal at any point of an involute is tangent to the circle.
Fig: Involute teeth
Let O1 and O2 be the fixed centres of the two base circles as shown in fig (a). Let corresponding involutes AB and A1B1 be in contact at point Q. MQ and NQ are normals to involutes at Q and are tangents to base circles. Since the normal of an involute at a given point is tangent drawn from that point to given base circle. Therefore the common normal MN at Q is also the common tangent to the two given base circles. We see that common normal MN intersects the line of centres O1O2 at fixed point P called pitch point. Therefore the involute teeth satisfy fundamental condition of constant velocity ratio.
From similar triangle O2NP and O1MP
O1M/O2N = O1P/ O2P = ω2/ω1 ... (i)
Which determines the ratio of the radii of the two base circles. The radii of the base circles is given by
O1M = O1Pcosφ and O2N = O2 P cosφ
Also the centre distance between the base circles
O1O2 = O1P + O2P = O 1M/ cosφ + O2N/ cosφ
Where φ is the pressure angle or the angle of obliquity. It is the angle which the common normal to the base circles i.e. MN makes with the common tangent to the pitch circles. When the power is being transmitted then the maximum tooth pressure is exerted along the common normal through pitch point. This force resolved into tangential and radial or normal components. These components act along and at right angles to common tangent to pitch circles.
If F is the maximum tooth pressure as shown in fig (b), then
Tangential force, FT = F cos φ and
Radial or normal force, FR = F sin φ.
∴ Torque exerted on the gear shaft = FT × r
Where r is pitch circle radius of the gear.
The tangential force provides the driving torque and the radial or normal force produces radial deflection of rim and bending of shafts.
Effect of Altering the Centre Distance on Velocity Ratio for an Involute Gears teeth
The velocity ratio for the involute teeth gears is given by
O1M/O2N = O1P/ O2P = ω2/ω1... (i)
Let, in fig (a), the centre of rotation of one of the gears is shifted from O1 to O1'. Then the contact point shifts from Q to Q '. The common normal to the teeth at point of contact Q ' is tangent to base circle because it has a contact between two involute curves and they are generated from base circle. Let tangent M'N' to base circles intersects O1′ O2 at pitch point P’. As a result of this the wheel continues to work correctly.
Now from similar triangles O2NP and O1MP,
O1M/O2N = O1P/ O2P ... (ii)
From similar triangles O2N'P' and O1'M'P',
O1′M′/ O2N' = O′1P1′/ O2P′ ... (iii)
But O2N = O2N', and O1M = O1' M'.
Therefore from equations (ii) and (iii),
O1P/ O2P= O1′P′/ O2P′
Thus we see that if the centre distance is changed within limit then the velocity ratio remains unchanged. However, the pressure angle increases (from φ to φ′) with the increase in the centre distance.
Length of Path of Contact
Fig: Lenth of path of contact
Consider a pinion driving the wheel as shown in fig. When pinion rotates in clockwise direction the contact between a pair of involute teeth begins at K on the flank near base circle of pinion or outer end of tooth face on the wheel and ends at L outer end of the tooth face on pinion or on flank near base circle of wheel. MN is the common normal at the point of contacts and common tangent to base circles. Point K is the intersection of the addendum circle of wheel and common tangent. The point L is intersection of addendum circle of pinion and common tangent. If the wheel is made to act as a driver and directions of motion are reversed then the contact between a pair of teeth begins at L and ends at K.
The length of path of contact is the length of common normal cutoff by the addendum circles of the wheel and pinion. So length of path of contact is KL which is the sum of the parts of the path of contacts KP and PL. The part of path of contact KP is known path of approach and part of the path of contact PL is known as path of recess.
Let
rA = O1L = Radius of addendum circle of pinion,
RA = O2K = Radius of addendum circle of wheel,
r = O1P = Radius of pitch circle of pinion, and
R = O2P = Radius of pitch circle of wheel.
From fig we find that radius of the base circle of pinion,
O1M = O1P cos φ = r cos φ
And radius of the base circle of wheel,
O2N = O2P cos φ = R cos φ
Now from right angled triangle O2KN,
\[KN = \sqrt {{{\left( {{O_2}K} \right)}^2} - {{\left( {{O_2}N} \right)}^2}} = \sqrt {{{\left( {{R_A}} \right)}^2} - {{\left( {R\cos \varphi } \right)}^2}} \]
And PN = O2Psinφ = R sinφ
∴ Length of the part of the path of contact, or the path of approach,
\[KP = KN - PN = \sqrt {{{\left( {{R_A}} \right)}^2} - {{\left( {R\cos \varphi } \right)}^2}} - R\sin \varphi \]
Similarly from right angled triangle O1ML,
\[ML = \sqrt {{{\left( {{O_1}L} \right)}^2} - {{\left( {{O_1}M} \right)}^2}} = {\sqrt {{{\left( {{r_A}} \right)}^2} - {{\left( {r\cos \varphi } \right)}^2}} ^{}}\]
And MP = O1Psin φ = rsin φ
∴ Length of the part of the path of contact, or path of recess,
\[PL = ML - MP = \sqrt {{{\left( {{r_A}} \right)}^2} - {{\left( {r\cos \varphi } \right)}^2}} - r\sin \varphi \]
∴ Length of the path of contact,
\[{\rm K}L = KP + PL = \sqrt {{{\left( {{R_A}} \right)}^2} - {{\left( {R\cos \varphi } \right)}^2}} + \sqrt {{{\left( {{r_A}} \right)}^2} - {{\left( {r\cos \varphi } \right)}^2}} - \left( {R + r} \right)\sin \varphi \]
References:
1. H.H. Mabie and C. F. Reinholtz, “Mechanism and Dynamics of Machinery”, Wiley.
2. J.S. Rao & R.V. Dukkipati Mechanisms and Machine Theory, New Age International (P) Limited..
3. J.E. Shigley and J.J. Uicker, Jr., “ Theory of Machines and Mechanisms”, McGraw Hill.
4. B. Paul, “Kinematics and Dynamics of Planar Machinery”, Prentice Hall.
5. C. E. Wilson, J.P. Sadler and W.J. Michels, “Kinematics and Dynamics of Machinery”, Harper Row.
Lesson
4. Spur Gears
Subject
Mechanical Engineering
Grade
Engineering
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