Planck’s Radiation Law and Solar Constant

Plank's law for short distance is Wien's law and for long wavelength is Rayleigh jeans law. This note provides us an information on Planck’s radiation law and solar constant.

Summary

Plank's law for short distance is Wien's law and for long wavelength is Rayleigh jeans law. This note provides us an information on Planck’s radiation law and solar constant.

Things to Remember

  • For shorter wave length \(\therefore E_{\lambda }d\lambda = \frac {8\pi hc\:e^{-\frac {h}{\lambda KT}}}{\lambda^5}d\lambda\) which is Wein's law.
  • For longer wavelength,\( E_{\lambda }d\lambda = \frac {8\pi KT}{\lambda ^4}d\lambda \)

which is Rayleigh Jeans law.

  • Wien’s Law holds for shorter wavelength while Rayleigh-Jeans law holds true for longer wavelength.
  • The solar constant is defined as the amount of solar energy received per minute by unit area of a perfectly black body placed at a mean distance of the earth from the sun, in absence of the atmosphere and at right angle to the direction of sun’s rays. 

MCQs

No MCQs found.

Subjective Questions

Q1:

Determine whether the following are terminating or repeating decimals. 

\(\frac{2}{5}\)


Type: Short Difficulty: Easy

Show/Hide Answer
Answer: <p>Solution</p>
<p>\(\frac{2}{5}\)</p>
<p>= \(\require{enclose}\begin{array}{r}0.4\\[-3pt]5\enclose{longdiv} {20}\\[-3pt]\underline{20} \end{array}\)&nbsp;</p>
<p>Here, Divident = 2</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; Divisor = 5</p>

Q2:

Determine whether the following are terminating or repeating decimals. 

\(\frac{1}{2}\)


Type: Short Difficulty: Easy

Show/Hide Answer
Answer: <p>Solution</p>
<p>\(\frac{1}{2}\)</p>
<p>= \(\require{enclose}\begin{array}{r}0.5\\[-3pt]2\enclose{longdiv} {10}\\[-3pt]\underline{10} \end{array}\)&nbsp;</p>
<p>&nbsp;Divident = 1</p>
<p>&nbsp; Divisor = 2</p>
<p>Here, \(\frac{1}{2}\)= 0.5 which is terminating decimal.&nbsp;</p>
<p>&nbsp;</p>

Q3:

Determine whether the following are terminating or repeating decimals.

\(\frac{11}{30}\)

 


Type: Long Difficulty: Easy

Show/Hide Answer
Answer: <p>&nbsp;Solution</p>
<p>=&nbsp;\(\frac{11}{30}\)</p>
<p>= \(\require{enclose}\begin{array}{r}0.366\\[-3pt]30\enclose{longdiv}{110}\\[-3pt]\underline{90}\\[-3pt]{200} \\[-3pt]\underline{180}\\[-3pt]\\{200}\\[-3pt]\underline{180}\\[-3pt]{20}\end{array}\)</p>
<p>Divident= 11</p>
<p>Divisor= 30</p>
<p>Here, \(\frac{11}{30}\) = 0.366 is also repeating decimal. So it is rational number.&nbsp;</p>
<p>&nbsp;</p>

Q4:

 Determine whether the following are terminating or repeating decimals.

\(\frac{7}{22}\)


Type: Long Difficulty: Easy

Show/Hide Answer
Answer: <p>&nbsp;Solution</p>
<p>=\(\frac{7}{22}\)</p>
<p>= \(\require{enclose}\begin{array}{r}1.31818\\[-3pt]22\enclose{longdiv}{70}\\[-3pt]\underline{66}\\[-3pt]{40} \\[-3pt]\underline{22}\\[-3pt]\\{180}\\[-3pt]\underline{176}\\[-3pt]{40}\\[-3pt]\underline{22}\\[-3pt]{180}\\[-3pt]\underline{176}\\{4}\end{array}\)</p>
<p>Divident= 7</p>
<p>Divisor= 22</p>
<p>Here, \(\frac{7}{22}\) = 0.31818 which is repeating decimal. So, \(\frac{7}{22}\) is a rational number.&nbsp;</p>

Q5:

What are whole numbers?


Type: Very_short Difficulty: Easy

Show/Hide Answer
Answer: <p>The set of all the natural along with zero is known as hole numbers.&nbsp;</p>

Q6:

What are a Rational number?


Type: Very_short Difficulty: Easy

Show/Hide Answer
Answer: <p>Any number that can be written in the form of \(\frac{p}{q}) where q&ne;0 is known as the &nbsp;rational number.&nbsp;</p>

Q7:

What does zero denote in Natural  Number System?


Type: Very_short Difficulty: Easy

Show/Hide Answer
Answer: <p>Zero(0) is neither positive integers nor negative integer. It is a natural number.&nbsp;</p>

Q8:

What are positive Integers?


Type: Very_short Difficulty: Easy

Show/Hide Answer
Answer: <p>The positive integers are those whose set are all positive natural numbers and &nbsp;it is denoted by Z<sup>+.</sup></p>

Q9:

What are integers?


Type: Very_short Difficulty: Easy

Show/Hide Answer
Answer: <p>Integers are the set of all positive and negative natural numbers inclusive of Zero. &nbsp;I t can be &nbsp;denoted by Zero(0).&nbsp;</p>

Q10:

Determine whether the following are terminating or repeating decimals.

\(\frac{1}{4}\)

 


Type: Short Difficulty: Easy

Show/Hide Answer
Answer: <p>Solution</p>
<p>=\(\frac{1}{4}\)</p>
<p>&nbsp;</p>
<p>=\(\require{enclose}\begin{array}{r}0.25\\[-3pt]4\enclose{longdiv}{10}\\[-3pt]\underline{8}\\[-3pt]{20}\\\underline{20}\end{array}\)</p>
<p>Divident = 1</p>
<p>Divisor= 4</p>
<p>Here, \(\frac{1}{4}\) = 0.25 which is terminating decimal.&nbsp;</p>

Q11:

Determine whether the following are terminating or repeating decimals.

\(\frac{1}{4}\)


Type: Short Difficulty: Easy

Show/Hide Answer
Answer: <p>Solution</p>
<p>\(\frac{1}{4}\)</p>
<p>=&nbsp;\(\require{enclose}\begin{array}{r}0.25\\[-3pt]4\enclose{longdiv} {10}\\[-3pt]\underline{8} \\[-3pt]20\\\underline{20}\end{array}\)&nbsp;</p>
<p>= &nbsp;Here, the quotient is 0.25. It is terminating after 2 decimals.&nbsp;</p>
<p>Divident= 1</p>
<p>Divisor = 4</p>
<p>&nbsp;</p>

Q12:

Determine whether the following are terminating or repeating decimals.

\(\frac{2}{9}\)


Type: Long Difficulty: Easy

Show/Hide Answer
Answer: <p>Solution</p>
<p>=\(\frac{2}{9}\)</p>
<p>= \(\require{enclose}\begin{array}{r}0.222\\[-3pt]9\enclose{longdiv}{20}\\[-3pt]\underline{18}\\[-3pt]{20} \\[-3pt]\underline{18}\\[-3pt]\\{20}\\[-3pt]\underline{18}\end{array}\)</p>
<p>Divident = 2</p>
<p>Divisor = 9</p>
<p>Here, \(\frac{2}{9}\) = 0.222 which is repeating decimal. So, it is also a rational number.&nbsp;</p>
<p>&nbsp;</p>

Q13:

 Determine whether the following are terminating or repeating decimals.

\(\frac{13}{8}\)


Type: Long Difficulty: Easy

Show/Hide Answer
Answer: <p>Solution</p>
<p>=&nbsp;\(\frac{13}{8}\)</p>
<p>= \(\require{enclose}\begin{array}{r}1. 625\\[-3pt]8\enclose{longdiv}{13}\\[-3pt]\underline{8}\\[-3pt]{50} \\[-3pt]\underline{48}\\[-3pt]\\{20}\\[-3pt]\underline{16}\\[-3pt]{40}\\[-3pt]\underline{40}\\{0}\end{array}\)</p>
<p>Divident = 13</p>
<p>Divisor = 8</p>
<p>Here, \(\frac{13}{8}\) = 1.625 which is terminating decimal.</p>

Q14:

What are the properties of rational numbers?


Type: Short Difficulty: Easy

Show/Hide Answer
Answer: <p>The properties of rational numbers are listed below:</p>
<ul>
<li>Any rational numbers can be written in a ratio.</li>
<li>It must be divided.</li>
<li>The decimals of rational members are either terminating or recurring.&nbsp;</li>
</ul>
<p>&nbsp;</p>

Q15:

Determine  whether the following  are terminating or repeating decimals.

\(\frac{1}{8}\)


Type: Long Difficulty: Easy

Show/Hide Answer
Answer: <p>Solution</p>
<p>=\(\frac{1}{8}\)</p>
<p>= \(\require{enclose}\begin{array}{r}0.25\\[-3pt]8\enclose{longdiv}{10}\\[-3pt]\underline{8}\\[-3pt]{20}\\[-3pt]\underline{16}\\[-3pt]{40}\\\underline{40}\end{array}\)</p>
<p>Here, Divident= 1</p>
<p>Divisor = 8</p>
<p>Since, \(\frac{1}{8}\) = 0.25 which is terminating decimal. So, it is rational number.&nbsp;</p>

Videos

Classify Rational Numbers
Add, Subtract, Multiply and Divide Integers
Types of Numbers (Number System)
Rules for Positive and Negative Numbers
Planck’s Radiation Law and Solar Constant

Planck’s Radiation Law and Solar Constant

Wein’s law and Rayleigh-jeans law from Planck’s law of radiation

According to plank’s Law we have,

$$E_{\lambda }d\lambda = \frac {8\pi hc}{\lambda ^5}\frac {1}{e^{\frac {hc}{\lambda KT} }-1} d\lambda $$


For shorter wave length \( e^{h}{\lambda KT} \) becomes large compared to unity and hence the Plank’s law reduces to

\begin{align*} E_{\lambda }d\lambda &= \frac {8\pi hc}{\lambda ^5}\frac {1}{e^{\frac {hc}{\lambda KT}}}d\lambda \\ \therefore E_{\lambda }d\lambda &= \frac {8\pi hce^{-\frac {h}{\lambda KT}}}{\lambda^5}d\lambda \\ \end{align*}

which is Wien’s law.

For longerwavelength,

\begin{align*} \therefore E_{\lambda }d\lambda &= \frac {8\pi hc}{\lambda ^5}\frac {1}{1 + \frac {hc}{\lambda KT}+\dots -1}d\lambda \\ E_{\lambda }d\lambda &= \frac {8\pi KT}{\lambda ^4}d\lambda \end{align*}
which is Rayleigh Jeans law. It is clear that Wien’s Law holds for shorter wavelength while Rayleigh Jeans law holds true for longer wavelength.

Deduction of Stefan’s constant from Planck’s Radiation Law

Total radiant energy in unit volume of an isothermal enclosure is

$$ E = \int _0^{\infty } E_{\lambda }\: d\lambda = \int \frac {8\pi hc}{\lambda ^5(e^{hc/ \lambda KT}- 1)}\: d\lambda \dots (1) $$

The total radiant energy in unit volume of an isothermal enclosure is also given by

\begin{align*} E &= AT^4 \dots (2) \\\end{align*}

where A is constant and T is the absolute temperature of enclosure

\begin{align*} \\ AT^4 &= 8\pi hc \int _0^{\infty }\frac {d\lambda }{\lambda ^5} \left (e^{\frac {hc}{\lambda KT}-1}\right )\dots (3) \\ \text {Putting,}\: x= \frac {hc}{\lambda KT} \\ \text {or,}\: \lambda &= \frac {hc}{xKT} \\ \therefore d\lambda &= \frac {-hdx}{x^2KT} \\ \end{align*}

Substituting these value in equation (3) we get \begin{align*}\ \\AT^4 &= 8\pi hc \int _0^{\infty } \frac {\frac {hc}{x^2KT}dx}{\left (\frac {xc}{xKT}\right )^5(e^x -1)} \\ &= \frac {8\pi K^4T^4}{h^3c^3}\int _0^{\infty } \frac {x^3dx}{e^x – 1} \\ \therefore AT^4 &= \frac {8\pi K^4T^4\pi ^4}{15h^3c^3}\:\left [\because \int _0^{\infty }\frac {x^3}{e^x – 1} = \frac {\pi ^4}{15}\right ] \\ \therefore A &= \frac {8\pi K^4\pi ^4}{15h^3c^3} \dots (4) \\ \end{align*}

\begin{align*} \text {Sine Stefan’s constant is given by,} \\ \sigma &= \frac {Ac}{4} \\ \therefore \sigma &= \frac {8\pi ^5 K^4}{15h^3c^3}\frac c4 = \frac {2\pi^5K^4}{15h^3c^2} \\ \end{align*}

Wien’s Constant (b)

According to Wien’s law, Wein’s constant
$$ b = \lambda _{m}T$$

Where \(\lambda _m\) is the wavelength for which the emitted energy is maximum. We have a relation

$$\lambda _m = \frac {hc}{4.965 KT}$$

$$ or, \: \lambda _mT = \frac {hc}{4.965} = 0.2896\: \text {cmK}$$

Solar Constant

Solar constant is defined as the amount of solar energy received per minute by unit area of a perfectly black body placed at a mean distance of the earth from the sun, in absence of the atmosphere and at right angle to the direction of sun’s rays. It is denoted by ‘S’.

Let E be the emissive power of sun, r be its radius. Then the radiant energy emitted by the sun per minute

$$4\pi r^2E\times 60 $$

S be the solar constant, R be the man distance between sun and earth, then the radiant energy absorbed by a perfectly black body having radius R as shown in the figure above is

\begin{align*}&= 4\pi R^2S \dots (2) \\ \text {In the absence of atmosphere,} \\ 4\pi R^2 S &= 4\pi r^2 E \times 60 \dots (3) \\ \text {According to Stefan’s law,}\\ E &= \sigma T^4 \dots (4) \\ \text {From equation}\: (3) and (4)\: \text {we get,} \\ 4\pi R^2 S &= 4\pi r^2 \sigma T^4 \times 60 \\ \text {or,}\: T^4 &= \left ( \frac Rr\right )^2 \frac {S}{60} \times \frac {1}{\sigma } \\ \therefore T &= \left [\left (\frac Rr\right )^2 \frac {S}{60}\times \frac {1}{\sigma } \right ]^{1/4} \dots (5) \\ \end{align*}

Equation (5) represents absolute temperature of sun in terms of Stefan’s constant and solar constant.

Bibliography

S.S. Singhal, J.P. Agarwal, Satya Prakash. heat and thermodynamics and statistical physics. pragati prakashan, 2010.

—. Heat and Thermodynamics and Statistical Physics. Pragati Prakashan, 2010.

Vatsyayan, Dr. Rakesh Ranjan. Refresher Course in Physics. kathmandu: Surya Book Traders, 2015.

Lesson

Black Body Radiation

Subject

Physics

Grade

Bachelor of Science

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