Pythagoras Theorem
Trigonometry is a branch of mathematics which concerned with the measurement of sides, angles and their relation to a triangle. The relationship between the three sides of a triangle is simply known as Pythagoras theorem. This note has information about Pythagoras Theorem.
Summary
Trigonometry is a branch of mathematics which concerned with the measurement of sides, angles and their relation to a triangle. The relationship between the three sides of a triangle is simply known as Pythagoras theorem. This note has information about Pythagoras Theorem.
Things to Remember
Pythagoras theorem states that the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
Pythagoras Theorem
Hypotenuse (h2) = Perpendicular (p2) + Base (b2)
or, h2 = p2 + b2
Where, h = \(\sqrt{p^{2}+ b^{2}}\)
p = \(\sqrt{h^{2}- b^{2}}\)
b = \(\sqrt{h^{2}- p^{2}}\)
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Pythagoras Theorem
Trigonometry
The word "Trigonometry" is derived from the Greek word "Tri-Gonia-Metron" where Tri means three, Gonia means angles and Metron mean measure. So, trigonometry is a branch of mathematics which concerned with the measurement of sides, angles and their relation to a triangle.
Pythagoras Theorem

The relationship between the three sides of a triangle is simply known as Pythagoras Theorem. The relation was given by the popular Mathematician Pythagoras which is called Pythagoras theorem.
In mathematics, the Pythagorean theorem, also known as Pythagoras's theorem, is a relation in Euclidean geometry among the three sides of a right triangle. It states that the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
According to this theorem "In any right-angled triangle, the area of the square on the hypotenuse is equal to the sum of the areas of squares of perpendicular and base".
By Pythagoras Theorem
Hypotenuse (h2) = Perpendicular (p2) + Base (b2)
or, h2= p2+ b2
From this theory we can derive,
h = \(\sqrt{p^{2} + b^{2}}\)
p = \(\sqrt{h^{2} - b^{2}}\)
b = \(\sqrt{h^{2} - p^{2}}\)
Lesson
Trigonometry
Subject
Optional Maths
Grade
Grade 8
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