Pranayama

Pranayama is a Sanskrit word meaning "extension of the breath" or "extension of the life force". This note explains what is pranayama and how it is beneficial for us.

Summary

Pranayama is a Sanskrit word meaning "extension of the breath" or "extension of the life force". This note explains what is pranayama and how it is beneficial for us.

Things to Remember

  • Pranayama is a Sanskrit word meaning "extension of the breath" or "extension of the life force". The word is composed of two Sanskrit words: "Prana", life force, or vital energy, (noted particularly as the breath), and "Yama", to extend or draw out. 
  • Bhastrika is one of the most important pranayamas. It is a very mysterious pranayama and not much is known about it.
  • Kapalabhati is an important part of Shatkarma, the yogic system of body cleansing techniques. The word kapal Bhatti is made up of two words: kapal meaning 'skull' and bhati meaning 'shining, illuminating.' 
  • Anulom Vilom (Alternate Nostril Breathing) is one of the most effective pranayama (breathing exercises) to purify the mind and body. 

MCQs

No MCQs found.

Subjective Questions

Q1:

Find the perimeter of a square flower-bed of side 20 m.


Type: Short Difficulty: Easy

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Answer: <p>Solution:</p> <p>Given, side(a) = 20m</p> <p>Perimeter of square flower-bed = 4a</p> <p>=4 x 20</p> <p>=80</p> <p>\(\therefore\) perimeter of square flower-bed = 80 m</p>

Q2:

Find the area and perimeter of a square room 35m.


Type: Long Difficulty: Easy

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Answer: <p>Solution:</p> <p>Given, side(a) = 35m</p> <p>Now,</p> <p>Area of square= a<sup>2</sup></p> <p>= (35m)<sup>2</sup></p> <p>= 1225m<sup>2</sup></p> <p>\(\therefore\) area of square = 1225</p> <p>Also,</p> <p>Primeter of square = 4a</p> <p>= 4 x 35m</p> <p>= 140m</p> <p>\(\therefore\) Perimeter of square = 140m</p>

Q3:

Find the area and perimeter of a rectangle field 12m long and 20 m wide.


Type: Long Difficulty: Easy

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Answer: <p>Solution:</p> <p>Given, length (l) =12 m and wide (b)=20 m</p> <p>Area of rectangle field = l x b</p> <p>=12m x 20m</p> <p>= 240m<sup>2</sup></p> <p>Perimeter of rectangle field = 2 (l+b)</p> <p>= 2 (12m + 20m)</p> <p>= 2 x 32m</p> <p>= 64m</p>

Q4:

Find the area and perimeter of a rectanguler room 25m long and 30m wide.


Type: Long Difficulty: Easy

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Answer: <p>Solution:</p> <p>Given, length (l) = 25m and wide (b) = 30m</p> <p>Area of a rectanguler room = lxb</p> <p>= 25m x 30m</p> <p>= 750m<sup>2</sup></p> <p>Perimeter of a rectanguler room = 2(l+b)</p> <p>= 2(25m+30m)</p> <p>= 2 x 55m</p> <p>= 110m</p>

Q5:

One side of a parallelogram is 14 cm. Its distance from the opposite side is 16.5 cm. Find the area of the parallelogram.


Type: Long Difficulty: Easy

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Answer: <p>Solution:</p> <p>Here, base = 14 cm and height = 16.5 cm</p> <p>Area of the parallelogram = base x height</p> <p>= 14 cm x 16.5cm</p> <p>= 231cm<sup>2</sup></p>

Q6:

Find the area of the parallelogram having distance from the opposite side is 12.5 cm and one side of a parallelogram is 10 cm.


Type: Long Difficulty: Easy

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Answer: <p>Solution:</p> <p>Here, base = 10cm and height = 12.5cm</p> <p>Area of a parallelogram = base x height</p> <p>= 10cm x 12.5cm</p> <p>=120cm<sup>2</sup></p>

Q7:

Find the area of a trapezium whose parallel sides are 14 cm and 26 cm and the distance between them is 10 cm.


Type: Short Difficulty: Easy

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Answer: <p>Solution:</p> <p>Area of the trapezium = \(\frac{1}{2}\) x (sum of parallel sides)xh</p> <p>= \(\frac{1}{2}\)x(14+26)x10</p> <p>= \(\frac{1}{2}\)x40x10 = 200cm<sup>2</sup></p>

Q8:

Find the area of a trapezium whose parallel sides are 10 cm and 30 cm and the distance between them is 10 cm.


Type: Short Difficulty: Easy

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Answer: <p>Solution:</p> <p>Area of the trapezium = \(\frac{1} {2}\) x (sum of parallel sides) x h</p> <p>= \(\frac{1}{2}\) x (20+30) x 10</p> <p>=\(\frac{1}{2}\) x 50 x 10</p> <p>= 250cm<sup>2</sup></p>

Q9:

Find the area of a rhombus, the length of whose diagonals are 24cm and 16.5cm.

 


Type: Short Difficulty: Easy

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Answer: <p>Solution:</p> <p>Area of the rhombus = \(\frac{1}{2}\) xd<sub>1</sub>d<sub>2</sub></p> <p>= \(\frac{1}{2}\) x 24 x 16.5</p> <p>=198cm<sup>2</sup></p>

Q10:

Find the area of a rhombus, whose length are 12cm and 14.5cm.

 


Type: Short Difficulty: Easy

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Answer: <p>Solution:</p> <p>Area of the rhombus = \(\frac{1}{2}\) x d<sub>1</sub>d<sub>2</sub></p> <p>= \(\frac{1}{2}\) x 12cm x 14.5cm</p> <p>= 87 cm<sup>2</sup></p>

Q11:

Find the circumference of a circle of radius 10.5 cm.


Type: Short Difficulty: Easy

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Answer: <p>Soution:</p> <p>The circumference of the circle is given by</p> <p>c =2\(\pi\)r</p> <p>=2\(\times\)\(\frac{22}{7}\)\(\times\)10.5</p> <p>=66 cm</p> <p>Thus, circumference=66 cm</p>

Q12:

Find the diameter of a circle whose circumference is 88 cm.


Type: Short Difficulty: Easy

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Answer: <p>Solution:</p> <p>We know that, c=2\(\pi\)r</p> <p>or, 88=2\(\times\)\(\frac{22}{7}\)\(\times\)r</p> <p>or, r=\(\frac{88\times7}{2\times22}\)\(\times\)r</p> <p>or, r=\(\frac{88 x 7 }{2 x 22}\)</p> <p>\(\therefore\) r=14 cm</p> <p>Thus, radius=14 cm</p>

Q13:

The diameter of a wheel of a van is 63 cm. Find the distancetravelled by the van during the period, the wheel makes revolutions.


Type: Long Difficulty: Easy

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Answer: <p>Solutions:</p> <p>Note that, in 1 revolution the car covers a distance equal to the circumference of the wheel.</p> <p>Now, the diameter of the wheel=63 cm</p> <p>Therefore, radius(r)=\(\frac{63}{2}\)cm</p> <p>Circumference of the wheel= 2\(\pi\)r</p> <p>=2\(\times\)\(\frac{22}{7}\)\(\times\)\(\frac{63}{2}\)</p> <p>=198 cm</p> <p>=1.98 m</p> <p>Here, the distance covered in 1 revolution=1.98 m</p> <p>Distance covered in 1000 revolutions=1.98\(\times\)1000</p> <p>=1980 m</p>

Q14:

The circumference of a circle is 44 cm.Find its area.


Type: Short Difficulty: Easy

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Answer: <p>Solution:</p> <p>Circumference= 44 cm</p> <p>So, 2\(\pi\)r=44</p> <p>or, r=\(\frac{44}{2\pi}\)</p> <p>or, r=\(\frac{44\times7}{2\times22}\)</p> <p>\(\therefore\) r=7 cm</p> <p>Area of the circle=\(\pi\)r<sup>2</sup></p> <p>=\(\frac{22}{7}\)\(\times\)7 \(\times\)7</p> <p>=154cm<sup>2</sup></p>

Q15:

The area of a circle is 164 cm2. Find its circumference.


Type: Short Difficulty: Easy

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Answer: <p>Solution:</p> <p>Area of a circle=154 cm<sup>2</sup></p> <p>So, \(\pi\)r<sup>2</sup>=154</p> <p>or, r<sup>2</sup>=\(\frac{154}{\pi}\)</p> <p>or, r<sup>2</sup>=\(\frac{154\times7}{22}\)</p> <p>or, r<sup>2</sup>=49</p> <p>or, r=\(\sqrt{49}\)</p> <p>\(\therefore\) r =7cm</p>

Q16:

One side of a parallelogram is 14 cm.Its distance from the opposite side is 16.5 cm.Find the area of the parallelogram.


Type: Short Difficulty: Easy

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Answer: <p>Solution:</p> <p>Here, base=14 cm and height= 16.5 cm</p> <p>Area of the parellogram= base\(\times\)height</p> <p>=14 cm\(\times\)16.5 cm</p> <p>=231 cm<sup>2</sup></p>

Q17:

Find the area of the given triangle.

.


Type: Long Difficulty: Easy

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Answer: <p>Solution:</p> <p>Base(b)=10 cm, height(h)=6 cm</p> <p>Area of \(\triangle\)PQR=\(\frac{1}{2}\)b\(\times\)h</p> <p>=\(\frac{1}{2}\)QR\(\times\)PQ</p> <p>=\(\frac{1}{2}\)10cm\(\times\)6cm</p> <p>=30cm<sup>2</sup></p> <p>Therefore, area of \(\triangle\)PQR=30cm<sup>2</sup></p>

Q18:

Find the perimeter of the given triangle.

.


Type: Short Difficulty: Easy

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Answer: <p>Solution:</p> <p>Given, AB=6cm, BC=5cm and CA=7cm</p> <p>Perimeter of \(\triangle\)ABC = AB + BC + CA</p> <p>= 6cm + 5cm + 7cm</p> <p>= 18cm</p> <p></p>

Q19:

Find the area of the following diagram

.


Type: Long Difficulty: Easy

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Answer: <p>Solution:</p> <p>Length of the rectangle(l)=5cm</p> <p>Breadth of the rectangle(b)=3.6cm</p> <p>Area of the rectangle=?</p> <p>By using formula,</p> <p>A= l\(\times\)b</p> <p>=5cm\(\times\)3.6cm</p> <p>=18.0cm<sup>2</sup></p>

Q20:

Find the perimeter and area of the rectangle of length 17 cm and breadth 13 cm.


Type: Short Difficulty: Easy

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Answer: <p>Solution:<br><br>Given: length = 17 cm, breadth = 13 cm</p> <p>Perimeter of rectangle = 2 (length + breadth)</p> <p>= 2 (17 + 13)cm</p> <p>= 2 &times; 30cm</p> <p>= 60cm</p> <p>Also,</p> <p>Area of rectangle = length &times; breadth</p> <p>= 17cm &times; 13cm</p> <p>= 221cm<sup>2</sup></p> <p></p>

Q21:

Find the breadth of the rectangular plot of land whose area is 660m2 and whose length is 33m. Find its perimeter.


Type: Short Difficulty: Easy

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Answer: <p>Solution:</p> <p>Given, Area of Rectangular plot = 660m<sup>2</sup> and Length = 33m</p> <p>Now, We know,</p> <p>Area of rectangle = Length \(\times\) breadth</p> <p>or, 660m<sup>2</sup> = 33m \(\times\) breadth</p> <p>or, breadth = \(\frac{660m^2}{33m}\)</p> <p>\(\therefore\) breadth = 20m</p> <p>Again,</p> <p>Perimeter of the rectangular plot = 2 (length + breadth)</p> <p>= 2 (33m + 20m)</p> <p>= 2 &times; 53m</p> <p>= 106m</p>

Q22:

Find the area of the rectangle if its perimeter is 48cm and its breadth is 6cm.


Type: Short Difficulty: Easy

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Answer: <p>Solution:</p> <p>Given, Perimeter of rectangle = 48cm and Breadth = 6cm</p> <p>We know, Perimeter of rectangle = 2(length + breadth)</p> <p>So, 48cm = 2(length + 6cm)</p> <p>or, \(\frac{48cm}{2} = length + 6cm</p> <p>or, 24cm = length + 6cm</p> <p>or, length = 24cm - 6cm</p> <p>\(\therefore\) length = 18cm</p> <p>Now,</p> <p>Area of rectangle = length &times; breadth</p> <p>= 18cm &times; 6cm</p> <p>= 108cm<sup>2</sup><br><br><br></p>

Q23:

A wire in the shape of rectangle of length 25 cm and breadth 17 cm is rebent to form a square. What will be the measure of each side?


Type: Short Difficulty: Easy

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Answer: <p>Solution:</p> <p>Perimeter of rectangle = 2(length + breadth)</p> <p>= 2(25cm + 17cm)</p> <p>= 2 &times; 42cm</p> <p>= 84cm</p> <p>Let the side of square be x.</p> <p>Then,</p> <p>Perimeter of square = 4x</p> <p>We know,</p> <p>Perimeter of rectangle = Perimeter of Square</p> <p>So, 84cm = 4x</p> <p>or, x = \(\frac{84cm}{4}\)</p> <p>\(\therefore\) x = 21cm</p> <p>Therefore, sides of square = 21cm.</p>

Q24:

 Find the circumference and area of radius 7 cm.


Type: Short Difficulty: Easy

Show/Hide Answer
Answer: <p>Solution: <br><br>Circumference of circle = 2&pi;r <br>= 2 &times; 22/7 &times; 7 <br>= 44 cm<br><br>Area of circle = &pi;r<sup>2</sup><br>= 22/7 &times; 7 &times; 7 cm<sup>2</sup><br>= 154 cm<sup>2</sup></p>

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Pranayama

Pranayama

Pranayama
Pranayama

Pranayama

Pranayama is a Sanskrit word meaning "extension of the breath" or "extension of the life force". The word is composed of two Sanskrit words: "Prana", life force, or vital energy, (noted particularly as the breath), and "Yama", to extend or draw out. It is a yogic discipline with origins in ancient India.

Bhastrika
Bhastrika

Bhastrika

Bhastrika is one of the most important pranayamas. It is a very mysterious pranayama and not much is known about it. However, many believe that it is a combination of Kapalbhati & Anulom Vilom pranayama. It is a breathing technique where breathing is forcible and through the nose, with equal time for inhalation and exhalation. Bhastrika Pranayama is aimed at keeping the inhalation cycle equal to exhalation, yet making breath deeper and longer. Deep breath inwards and long exhalation outwards with equal time intervals constitutes this pranayama technique.

Be seated in a comfortable posture. Padmasana (crossed leg) and Vajrasana are the ideal yoga postures to practice pranayama. Place your hands on your knees. Feel relaxed. Focus on your breathing pattern and be relaxed.

  1. Breathe in by inhaling forcefully through both the nostrils. Make sure that your lungs are filled with air. Once you inhale fully, exhale with great force making the hissing sound.
  2. In Bhastrika pranayama, one needs to apply force while breathing in and breathing out. You can determine how much speed to apply while inhaling and exhaling keeping in mind your health and endurance power.
  3. When you breathe in while performing Bhastrika pranayama, your abdominal should not blow up. Instead, your chest area should blow up. Repeat the procedure for 5 to 10 times.
  4. You have successfully completed Bhastrika pranayama. One should perform Bhastrika pranayama for 5 minutes every day. Those who have high blood pressure or heart disease should not practice Bhastrika pranayama.
Kapalvati
Kapalbhati

Kapalbhati

Kapalbhati is an important part of Shatkarma, the yogic system of body cleansing techniques. The word kapalbhati is made up of two words: Kapal meaning 'skull' and Bhati meaning 'shining, illuminating.' Due to the process, the organs in and under the skull mainly the brain, small brain and any of the spaces inside the head that are connected to the back of the nose (sinus) are influenced in a good manner. Hence, the word is used in that way. It is intended mainly for cleaning the cranial sinuses but has many other effects including curing anemia, according to the Gheranda Samhita and other sources. The Technique of Kapalabhati involves short and strong forceful exhalations and inhalation happens automatically.

  1. Elongate your spine upwards, lengthen your neck and subtly bring your chin back and in like a soldier at attention. This will align the spine with the back of your head.
  2. Close your eyes.
  3. Have your hands in Gyan Mudra. In Gyan Mudra,have your thumb tips and index finger meeting, with the wrists resting gently on the knees and the palms turned slightly upwards.
  4. Relax your stomach muscles.
  5. Now expel the air as forcefully as you are comfortable with through the nose. This should cause the abdominal muscles to contract sharply and should draw the abdomen inwards towards the spine (like when you suck in your stomach). Then allow the inhalation to occur completely passively without any additional effort. To repeat, the exhalation is done using conscious sharp force while the inhalation is just a recoil action bringing the air back into the lungs. All the breathing takes place through the nose. Right after the passive inhalation, exhale again forcefully and continue at a steady rhythm.
  6. Do a round of 10 repetitions.
  7. Work your way up to doing 5 rounds, while taking a break between each round.
Anulom Vilom
Anulom Vilom

Anulom Vilom

Anulom Vilom (Alternate Nostril Breathing) is one of the most effective pranayama (breathing exercises) to purify the mind and body. Anulom Vilom offers benefits in curing most of the internal body conditions and is very useful in releasing stress and anxiety. Anulom Vilom pranayama can be performed by people of all ages. It will help to practice this breathing exercise in a peaceful place like near a river or in a garden with plenty of greeneries.

  1. Close your eyes and relax. Sit in this position for a couple of minutes till you settle down.
  2. Close your right nostril with your right thumb
  3. Breathe in from your left nostril. Hold the breath for a couple of seconds.
  4. Open right nostril and close left nostril with middle and ring finger
  5. Breath out from right nostril.
  6. Breathe in from right nostril, close the right nostril
  7. Open left nostril and breathe out.
  8. Repeat again, steps 1 through 7.

Lesson

Yoga

Subject

Health and Physical Education

Grade

Grade 8

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