Congurency and Similarities
Two triangles are congruent if they have exactly the same three sides and exactly the same three angles. Similar triangle has the same shape, but the size may be different. Two triangles are similar if and only if the corresponding sides are in proportion and the corresponding angles are congruent.
Summary
Two triangles are congruent if they have exactly the same three sides and exactly the same three angles. Similar triangle has the same shape, but the size may be different. Two triangles are similar if and only if the corresponding sides are in proportion and the corresponding angles are congruent.
Things to Remember
- There is three easy way to prove similarity. If two pairs of corresponding angles in a pair of triangles are congruent, then the triangles are similar.
- When the three angle pairs are all equal, the three pairs of the side must be proportion.
- When triangles are congruent and one triangle is placed on the top of other sides and angles that are in the same position are called corresponding parts.
- Congruent and similar shapes can make calculations and design work easier.
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Congurency and Similarities
Congruent Triangles
The triangles having same size and shape are called congruent triangles. Two triangles are congruent when the three sides and three angles of one triangle have the measurements as three sides and three angles of another triangle. The symbol for congruent is ≅.
In the following figure, ΔABC and ΔPQR are congruent. We denote this as ΔABC ≅ ΔPQR.
Postulate and Theorems for Congruent Triangles
Postulate (SAS)
If two sides and the angle between them in one triangle are congruent to the corresponding parts in another triangle, then the triangles are congruent.
In the given figure,
AB ≅ PQ Sides (S)
∠B ≅ ∠Q Angle (A)
BC ≅ QR Side (S)
Therefore, ΔABC ≅ ΔPQR
Theorem (ASA)
A unique triangle is formed by two angles and the included side.
Therefore, if two angles and the included side of one triangle are congruent to two angles and the included side of the another triangle, then the triangles are congruent.
In the figure,
∠B ≅ ∠E Angle (A)
BC ≅ EF Side (S)
∠C ≅ ∠F Angle (A)
Therefore, ΔABC ≅ ΔDEF
Theorem ( AAS)
A unique triangle is formed by two angles and non-included side. Therefore, if two angles and the side opposite to one of them in a triangle are congruent to the corresponding parts in another triangle, then the triangles are congruent.
In the figure,
∠A ≅ ∠X Angle (A)
∠C ≅ ∠Z Angle (A)
BC ≅ YZ Side (S)
Therefore, ΔABC ≅ ΔXYZ
Theorem (SSS)
A unique triangle is formed by specifying three sides of a triangle, where the longest side (if there is one) is less than the sum of the two shorter sides.
Therefore, if their sides of a triangle are congruent to three sides of another triangle, then the triangles are congruent.
In the figure
AB ≅ PQ Sides (S)
BC ≅ QR Sides (S)
CA ≅ RP Sides (S)
Therefore, ΔABC ≅ ΔPQR
Similar Triangles
Methods of providing triangles similar
- If the corresponding sides of a triangle are proportion to another triangle then the triangles are similar.
Example
If∠A ≅ ∠D and ∠B ≅ ∠E, Then ΔABC ∼ ΔDEF - If the corresponding angle of a triangle is congruent to another triangle then, the triangles are similar.
Example
If \(\frac{AB}{DE}\) = \(\frac{BC}{EF}\) = \(\frac{AC}{DF}\), then ΔABC ∼ ΔDEF - Conversing first and the second method we can prove triangle similar as their sides being proportional and angles congruent.
Example
∠A ≅ ∠D and \(\frac{AB}{DE}\) = \(\frac{AC}{DF}\) then ΔABC ∼ ΔDEF
In case of overlapping triangles
When the lines are parallel in a triangle, then they intersect each other which divides the sides of a triangle proportionally.
Verification:
In ΔPQR and ΔSPT
Statements | Reasons |
ST⁄⁄QR | Given |
\(\angle\)PST \(\cong\) \(\angle\)QSR | Corresponding angles |
ΔPQR \(\cong\) ΔSPT | Common Angle P |
\(\frac{PS}{SQ}\) = \(\frac{PT}{TR}\) | ST⁄⁄QR |
Example
Given the following triangles, find the length of x.
Solution:
The triangles are similar by AA rule.So, the ratio of lengths are equal.
\(\frac{6}{3}\) = \(\frac{10}{x}\)
or, 6x = 30
or, x = \(\frac{30}{6}\)
\(\therefore\) x = 5 cm
Lesson
Geometry
Subject
Compulsory Maths
Grade
Grade 8
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