Resonance and Velocity of Transverse Wave along a Stretched String
When a body capable of vibration is displaced and then allowed to vibrate freely, it will vibrate with a frequency which is called the natural frequency. This note provides us an information on resonance and velocity of a transverse wave along a stretched string.
Summary
When a body capable of vibration is displaced and then allowed to vibrate freely, it will vibrate with a frequency which is called the natural frequency. This note provides us an information on resonance and velocity of a transverse wave along a stretched string.
Things to Remember
When a body capable of vibration is displaced and then allowed to vibrate freely, it will vibrate with a frequency which is called the natural frequency.
If an external periodic force is applied on the body and the body vibrates with the frequency of the force, the motion is called the forced vibration.
The two conditions for occurring the resonance are the frequency of applied force must be equal to the natural frequency of the system and the applied force must be equal to the vibrating system.
MCQs
No MCQs found.
Subjective Questions
Q1:
What are the sign and symptoms of foreign body in nose ?
Type: Short Difficulty: Easy
<li>Pain or difficulty breathing through that side of the nose.</li>
<li>Nasal bleeding is also common symptom because the tissues of the nose can be easily scratched.</li>
<li>Vomiting : Because blood is quite nauseating , a patient may vomit , which can appear black or bloody.Sinusitis: Sinuses are all connected to the nasal passages</li>
<li>Complaint of choking ,wheezing ,difficulty, breathing , or inability to talk if the FB from the nose is pushed back into the throat .</li>
</ul>
<p> </p>
Q2:
What are the first aid management of foreign body in nose ?
Type: Long Difficulty: Easy
<ol>
<li>An object that is simply stuck in the nose and not causing another symptom can usually wait until morning or the following day for removal.</li>
<li>Don’t probe at the object with a cotton swab or other tool.</li>
<li>Don’t try to inhale the object by forcefully breathing in . Instead ,breathe through your mouth until the object is removed.</li>
<li>If only one nostril is affected , close the opposite nostril by applying gentle pressure and then blow out gently through the affected nostril.</li>
<li>A sneeze will actually produce much more force and is an alternative way to push the object forward and out of the nose</li>
<li>Gently removed the object if it's visible and you can easily grasp it with tweezers .
<ul>
<li>Don’t try to remove an object that isn't visible or easily grasped</li>
</ul>
</li>
<li>A parent or caregiver can attempt to remove the object by sealing their mouth over the child's mouth and closing the unaffected nostril with their finger.</li>
<li>Blowing a quick puff of air into the child's mouth has frequency resulted in the object coming out the nostril onto the caregiver check</li>
</ol>
Videos
foreign body in nose removal technique

Resonance and Velocity of Transverse Wave along a Stretched String
Resonance
When a body capable of vibration is displaced and then allowed to vibrate freely, it will vibrate with a frequency which is called the natural frequency. If an external periodic force is applied on the body and the body vibrates with the frequency of the force, the motion is called the forced vibration. Forced vibration leads to resonance. Resonance is the specific response of a system which is capable of vibrating with a certain frequency to an external force acting with the same frequency. For example, A suspension bridge has its own natural frequency. If the frequency of vibration coming out of marching soldier through the bridge is equal to the natural frequency of the bridge, then the bridge will vibrate violently with large amplitude and may collapse. That’s why the soldiers are ordered to break the steps while crossing the bridge.
The two conditions for occurring the resonance are
- The frequency of applied force must be equal to the natural frequency of the system,
- The applied force must be equal to the vibrating system.
The graph of the amplitude of vibration and frequency of forced vibration is shown below. The amplitude is large if the damping is small and vice versa.

Resonance air column tube: measurement of velocity of sound
The apparatus consists of a glass tube of length about one-meter and diameter 4 cm fitted on a vertical board with a meter scale attached to it. The tube is connected at its lower end by a rubber tube to reservoir which can be slided up and down. The tube and a part of the reservoir is filled with water. A tuning fork of known frequency is set into vibration and held horizontally above the mouth of the tube. The vibrating prongs of the tuning fork force the air in the tube to vibrate. As the vibration is forced, the frequency of tuning fork is same as the fundamental frequency of the pipe and the air inside the pipe is set into resonance by the periodic force. The length of air column in the tube is noted which is the first resonating length denoted by L1. Let 'e' be the end correction and at the fundamental mode of vibration,
\begin{align*} L_1 + e &= \frac {\lambda }{4} \\ \text {or,}\: \lambda &= 4(L_1 + e) \dots (i) \\ \end{align*}
Now, the length of air column is increased till another loud sound is heard with the same tuning fork.This is called the second resonance and this corresponds to the first overtone. Length of air column for is resonance is three times the length of the first resonance. So,
\begin{align*} L_2 + e &= \frac {3\lambda }{4} \\ \text {or,} \: 3\lambda &= 4(L_2 + e) \dots (ii) \\ \text {Subtracting equation} \: (i)\: \text {from equation} \: (ii), \text {we have} \\ 2\lambda &= 4(L_2 – L_1) \\ \text {or,} \: \lambda &= 2(L_2 –L_1) \\ \text {Knowing the frequency of the tuning fork,} \\ \text { v can be calculated as} \\ v &= f\lambda = 2f(L_2 – L_1) \dots (iii) \\ \end{align*}
\begin{align*} L_1 + e &= \frac {\lambda }{4} = \frac {v}{4f} \\ \text {or,} L_1 &= \frac {v}{4f} – e \end{align*} The velocity of sound can be calculated at 0oC using the relation as \begin{align*} v_o &= v\sqrt {\frac {T_o}{T}} \\ &= v\sqrt {\frac {273}{273 + \theta }} \\ \end{align*}At STP, velocity of aound can be calculated with correction of humidity as \begin{align*} v_o &= \sqrt {\frac {P -0.35\times f}{p}}\sqrt {\frac {273}{273 + \theta }} \end{align*}where f is the aqueous tension or saturated vapour pressure of water at lab temperature \(\theta \).
Velocity of Transverse Wave along a Stretched String
Suppose a stretched string. Consider a single symmetric pulse moving from left to right along the string with speed, v as shown in the figure. For convenience, we can consider a frame of reference in which the pulse remains stationary and then, we run along the pulse, keeping it constantly in view. In this frame, the string appears to move from right to left with the speed v.
Consider a small segment AB of the pulse of length DL forming an arc of a circle of radius R and subtending an angle 2θ at the centre, O of the circle. A tension T in the string pulls tangentially on this segment at each end. The horizontal component Tcos θ at two ends of the pulse cancel each other while the vertical components add to form a radial restoring force F given by
\begin{align*} F &= 2(T\sin\theta ) 2T\theta = T2\theta \\ \text {where } \: \sin \theta = \theta \: \text {for small angle.} \\ \text {The small angle can be written as} \: 2\theta = \Delta L/R.\\ \text {If} \: \mu \: \text {is the mass per unit length or linear density of the string,} \\ \text { the mass of the segment is } \\ m &= \mu \:\Delta L \\ \text {Since the string segment is moving in an arc of a circle,} \\ \text { this force acts as a centripetal force } \\ \text {producing a centripetal acceleration towards the centre of the circle} \\ \text {given by} \\ a &= \frac {v^2}{R} \\ \text {So the centripetal force,} \\ F &= \frac {mv^2}{R} \\\text {or,} \: T2\theta &= \frac {\mu \Delta Lv^2}{R} \\ \text {or,} \: \frac {T\Delta L}{R} &= \frac {\mu \Delta Lv^2}{R} \\ \text {or,}\: T &= \mu \: v^2 \\ \text {or,} \: v &= \sqrt {\frac {T}{\mu }} \\ \end{align*}The frequency of the wave is fixed entirely by whatever generates the wave as,\begin{align*} v &= \lambda f \\ \text {or,} \: f &= \frac {v}{\lambda } = \frac {1}{\lambda } \sqrt {\frac {T}{\mu }} \\ \end{align*}
Reference
Manu Kumar Khatry, Manoj Kumar Thapa, Bhesha Raj Adhikari, Arjun Kumar Gautam, Parashu Ram Poudel. Principle of Physics. Kathmandu: Ayam publication PVT LTD, 2010.
S.K. Gautam, J.M. Pradhan. A text Book of Physics. Kathmandu: Surya Publication, 2003.
Lesson
Waves in Pipes ans Strings
Subject
Physics
Grade
Grade 12
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