Law of Variable Proportion

The law of variable proportional explains how the output changes when one factor of production is made variable keeping other factors constant. In this law, the unit of labour change by keeping capital constant .

Summary

The law of variable proportional explains how the output changes when one factor of production is made variable keeping other factors constant. In this law, the unit of labour change by keeping capital constant .

Things to Remember

  1. Short run : Period of time in which quantities of one or more production factors cannot be changed.
  2. Long run: Period of time in which quantities of all factors of production are variable.
  3. Amount time needed to make all production input are variable.
  4. Law of variable proportion is also called short run production function.

MCQs

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Subjective Questions

Q1:

What do you mean by statistics ?


Type: Very_short Difficulty: Easy

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Answer: <p>Statistics is the branch of mathematics which deals with datas.</p>

Q2:

What do you mean by median ?


Type: Very_short Difficulty: Easy

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Answer: <p>Those data which divides the given set of data into two equal halves is called median .</p>

Q3:

What is the formula to calculate  median in individual series ?


Type: Very_short Difficulty: Easy

Show/Hide Answer
Answer: <p>The formula to calculate median in individual series;</p>
<p>Median&nbsp; ( Md ) = value of \(\frac{(n+1)^{th}}{2}\)item</p>

Q4:

In which order the data median must be arranged ?


Type: Very_short Difficulty: Easy

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Answer: <p>The data median must be arranged in either ascending&nbsp;or descending order .</p>

Q5:

Into how many parts median divides the set of data ?


Type: Very_short Difficulty: Easy

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Answer: <p>Median divides&nbsp;the set of data into &nbsp;two parts .</p>

Q6:

1.Calculate the mean from the data given below .

Marks  10  20   30   40   50 
No. of students  2  4  7   4  3

Type: Long Difficulty: Easy

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Answer: <p>Solution:</p>
<p><strong>Calculation of missing frequency</strong></p>
<table style="height: 140px;" width="208">
<tbody>
<tr>
<td>Marks ( x )</td>
<td>No of stdents (&nbsp;&fnof; )&nbsp;</td>
<td>&nbsp;&fnof;x &nbsp;</td>
</tr>
<tr>
<td>&nbsp;10</td>
<td>2</td>
<td>20</td>
</tr>
<tr>
<td>&nbsp;20</td>
<td>4</td>
<td>80</td>
</tr>
<tr>
<td>&nbsp;30</td>
<td>7
<p>&nbsp;</p>
</td>
<td>210</td>
</tr>
<tr>
<td>&nbsp;40</td>
<td>4</td>
<td>160</td>
</tr>
<tr>
<td>&nbsp;50</td>
<td>3</td>
<td>150</td>
</tr>
<tr>
<td>&nbsp;</td>
<td>&sum;&fnof;= N = 20</td>
<td>&sum;&fnof;x=620 &nbsp;</td>
</tr>
</tbody>
</table>
<p>Now ,&nbsp;</p>
<p>Mean &nbsp;\(\overline{X}\) = \(\frac{ &sum;&fnof;&chi;}{N}\)</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; =&nbsp; \(\frac{620}{20}\)=31</p>
<p>Hence , mean marks = 31 .</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp;</p>

Q7:

Find the value of a from the data given below whose mean is 17 .

 X 5 10 15 20 25 30
ƒ 2 5 a 7 4 2

Type: Long Difficulty: Easy

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Answer: <p>Solution :</p>
<p>Calculation of missing frequency</p>
<table>
<tbody>
<tr>
<td>X</td>
<td>&fnof;</td>
<td>Fx</td>
</tr>
<tr>
<td>5</td>
<td>2</td>
<td>10 &nbsp; &nbsp;</td>
</tr>
<tr>
<td>10</td>
<td>5</td>
<td>50</td>
</tr>
<tr>
<td>15 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;</td>
<td>a</td>
<td>15a</td>
</tr>
<tr>
<td>20</td>
<td>7</td>
<td>140</td>
</tr>
<tr>
<td>25</td>
<td>4</td>
<td>100</td>
</tr>
<tr>
<td>30</td>
<td>2</td>
<td>60</td>
</tr>
<tr>
<td>&nbsp;</td>
<td>&sum;&fnof;=20 + a &nbsp; &nbsp; &nbsp;</td>
<td>&sum;&fnof;x = 360 + 15a</td>
</tr>
</tbody>
</table>
<p>We know ,&nbsp;</p>
<p>Mean \(\overline{X}\)=\(\frac{&sum;&fnof;x}{N}\)</p>
<p>According to &nbsp;the question ,</p>
<p>Mean = 17</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;17=\(\frac{360 + 15a}{20 + a }\)</p>
<p>or17 ( 20 + a ) =360 + 15a</p>
<p>or340 + 17a =&nbsp;360 + 15a</p>
<p>or17a - 15a &nbsp;= 360 - 340</p>
<p>&nbsp;or, &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 2a = 20</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &there4;&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;a = 10</p>

Q8:

Find the median from the set of  data  given below .

3 ,7, 9,10,15 .

 


Type: Short Difficulty: Easy

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Answer: <p>Solution :</p>
<p>Here, the data are 3 ,7 , 9 , 10 , 15&nbsp;</p>
<p>Which are already&nbsp;in ascending&nbsp; order .</p>
<p>So , number of data ( n ) = 5</p>
<p>Now , Median ( Md ) = value of \(\frac{( n + 1 )^{th}}{2}\)item</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; =value of \(\frac{( 5 + 1 )^{th}}{2}\)item</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;=value of \(\frac{6}{2}^{th}\)item&nbsp;</p>
<p>&there4; Median ( Md ) = 9 .</p>

Q9:

Find the median from the given data :20 , 16 , 12 , 10 , 24 , 28 , 30 , 32 ,


Type: Long Difficulty: Easy

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Answer: <p>Solution :</p>
<p>Here , The given data are&nbsp;</p>
<p>20, 16, 12, 10 , 24, 28, 30, 32 .</p>
<p>Since the data are not arranged , arranging&nbsp;them in ascending &nbsp;order we get 10, 12, 16, 20, 24, 28, 30, 32</p>
<p>Now , number of data (n) = 8</p>
<p>So, Median (Md ) = value of \(\frac{(8+1)^{th}}{2}\)item</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= value of &nbsp;\(\frac{9}{2}^{th}\) item</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= value of &nbsp;4.5<sup>th</sup>item&nbsp;</p>
<p>Now ,&nbsp;4.5<sup>th</sup>item &nbsp;is not positive so,&nbsp;4.5<sup>th</sup>item is the mean of&nbsp;4.5<sup>th</sup>item and 5<sup>th</sup>item&nbsp;</p>
<p>So, median (Md) =\(\frac{ value of &nbsp;4^{th}item + value of&nbsp;5^{th}item }{2}\)</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= \(\frac{20\ +\ 24}{2}\)</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;=\(\frac{44}{2}\)</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;=22&nbsp;</p>
<p>&there4; Md = 22.</p>

Q10:

The average of 18 ,  11, 14, p, 17 is 14 .Find the value of p.


Type: Short Difficulty: Easy

Show/Hide Answer
Answer: <p>Solution :</p>
<p>The dates are 18, 11, 14, p, 17,</p>
<p>Number of dates (n) = 5&nbsp;</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &sum;x &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 18 + 11 + 14 + p + 17&nbsp;</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; =60 + p&nbsp;</p>
<p>Now, we know , mean \(\overline{X}\)= 14</p>
<p>So, mean \(\overline{X}\) = \(\frac{&sum;X}{n}\)</p>
<p>or, 14 = \(\frac{60 + p}{5}\)</p>
<p>or, 70=60 + p</p>
<p>or, 70-60 = p</p>
<p>or, 10= p</p>
<p>&there4; The value of p is 10 .</p>

Q11:

Find the mean of 1, 2, 3, 4, 5.


Type: Short Difficulty: Easy

Show/Hide Answer
Answer: <p>Solution ,&nbsp;</p>
<p>Here the datas are &nbsp;1, 2, 3, 4, 5.</p>
<p>number of datas&nbsp;( n ) = 5</p>
<p>&sum;x = 1 + 2+3+4+5</p>
<p>=15</p>
<p>Now, mean \(\overline{(X)}\)=\(\frac{&sum;X}{n}\)</p>
<p>=\(\frac{15}{5}\)</p>
<p>=3&nbsp;</p>

Videos

Statistics - Find the mean
Statistics - Find the median
Examples of mean median and mode
Law of Variable Proportion

Law of Variable Proportion

LAW OF VARIABLE PROPORTION

The Law of Variable Proportion explains how the output changes when one factor of production is made variable keeping other factors constant. In other words, it refers to the input-output relation when output is increased by varying the quantity of one input.In this law, the unit of labour change by keeping capital constant . As a number of fixed factors,capital is fixed then fixed factor and variable factor can be combined together in varying proportion. So, it is also called " The Law of Proportionality".

source:www.authorstream.com
source:www.authorstream.com

STATEMENTOF THE LAW

If we increase the quantity of variable factor keeping a number of fixed factors constant, then the total production initially increase at increasing rate, then the increase at decreasing rate becomes minimum and ultimately, the total production begins to fall. This law is also called "Short Run Production Function". The short run production function can be expressed as:

Q = f(K, L)

Where,

Q = Output

L = Variable input labour

K = Fixed input capital

According to PA Samuelson," An increase in some inputs relative to other fixed inputs will cause an output to income in a given state of technology, but after a point, the extra output resulting from the same auditions of extra inputs will become less and less."

In this law of variable proportion, we can see the changing capital labour ratio.

ASSUMPTIONS

  • The technology is fixed.
  • Variable inputs are homogeneous.
  • Short run production
  • At least one factor of production should be fixed.
  • Inputs are used in varying production.

SCHEDULE ANDFIGURE

We can further explain this law by the following hypothetical table/schedule.

Unit of Labour

Total Production

Marginal Product

Average Product

Returns

0

0

0

0

Increasing

1

5

5

5

2

15

10

10

3

30

15

15

4

50

10

15

5

60

5

10

Diminishing

6

60

0

5

7

50

-5

3

Negative

We can plot the data in graph, we obtain TP, MP and AP curve like as below;

Figure: Law of variable proportion
Figure: Law of variable proportion

In the above figure TP, AP and MP are shown in Y-axis and unit of labour are shown in the X-axis. In all the curves above, we can see that TP, AP, MP initially increase become maximum and fall. The point to be noted is that MP become negative but TP and APremain positive. When AP1is in its highest point,MP1has started to fall but Tp is still increasing. Again when TP reaches its highest point, MP becomes zero and AP start to fall. Finally, when TP starts to fall, MP becomes negative and AP is still falling but it remains positive. The above figure illustrates three stage of short run production process.

STAGE I

Stage I is called the stage of increasing returns. This stage starts from the origin and ends when Ap is maximum.

The main reasons for increasing returns are:

  • The proportion of fixed factors is greater than the quality of variable factors.
  • When the producer increases the quantity of the factors, output increase due to the complete utilisation of the indivisible factors.
  • The efficiency of variable factors goes up as more unit of variable factors are employed.

Stage II

Stage II is also known as the stage of diminishing returns. This stage starts from the point of maximum AP and ends when MP is equal to zero. In this total product (TP) continues to increase at a decreasing rate till it reaches to its maximum value.

Reason for decreasing returns are:

  • The proportion of variable factors is greater than the quantity of fixed factors.
  • Total output diminishes because there is a limit to the full utilisation of indivisible factors.
  • Due to the imperfect substitutability of factors input.

Stage III

Total output falls in this stage. The marginal product accordingly is falling and become negative. The average product continues to fall in this stage as well. It all because managerial complexities.

APPLICATIONOFLAW OF VARIABLE PROPORTION

The Law of Variable Proportion is mostly applied in agriculture due to following reasons:

  • Agricultural production is influenced by the natural factors
  • Decreasing fertility of soil
  • Seasonal dependence of agriculture
  • Problem of supervision

Besides the agriculture, the law of variable proportion is also applied on different sectors of an economy like:

  • Applicable in river or tank fisheries
  • Applicable to mines and brickfields
  • Applicable to forest products
  • Applicable to construction of building

(Jha, Bhusal and Bista)(Karna, Khanal and Chaulagain)(Khanal, Khatiwada and Thapa)

Bibliography

Jha, P.K., et al. Economics II. Kalimati, Kathmandu: Dreamland Publication, 2011.

Karna, Dr.Surendra Labh, Bhawani Prasad Khanal and Neelam Prasad Chaulagain. Economics. Kathmandu: Jupiter Publisher and Distributors Pvt. Ltd, 2070.

Khanal, Dr. Rajesh Keshar, et al. Economics II. Kathmandu: Januka Publication Pvt. Ltd., 2013.

Lesson

Theory of Production

Subject

Economics

Grade

Grade 12

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