Nutrition And Digestive Organs
introduction to nutrition and their types along with their function and uses in our daily life
Summary
introduction to nutrition and their types along with their function and uses in our daily life
Things to Remember
Nutrition
A autotropic nurtion
B Heterotropic nutrition
C heterotriphic Nutrition
macro nutrition -
Deficiency of nutrition
Oral Cavity , teeth, tongue
Digestive organs
MCQs
No MCQs found.
Subjective Questions
Q1:
Define triangle?
Type: Very_short Difficulty: Easy
Q2:
What is a reference angle ?
Type: Very_short Difficulty: Easy
Q3:
What is hypotenuse ?
Type: Very_short Difficulty: Easy
Q4:
What is perpendicular ?
Type: Very_short Difficulty: Easy
Q5:
What is a base ?
Type: Very_short Difficulty: Easy
Q6:
Find the unknown side from the given right angled triangles .

Type: Long Difficulty: Easy
<p>Let, PQR be a right angled triangle where right angled at Q .</p>
<p>So, PQ = 3 cm </p>
<p> QR = 4 cm </p>
<p> PR = ?</p>
<p>We know, in right angled PQR ,</p>
<p> h<sup>2 </sup>= p<sup>2 </sup>+ b<sup>2</sup></p>
<p>so,( PR )<sup>2</sup>= ( PQ )<sup>2</sup> + ( QR )<sup>2</sup></p>
<p>(PR)<sup>2</sup> = (3cm)<sup>2</sup> + (4cm)<sup>2 </sup></p>
<p>(PR)<sup>2</sup> = 9 cm + 12 cm</p>
<p>(PR)<sup>2</sup> = 25 cm<sup>2</sup></p>
<p>or, (PR )<sup>2</sup>= ( 5cm )<sup>2</sup></p>
<p>∴ PR = 5 cm .</p>
<p>Hence , the unknown side PR = 5 cm .</p>
Q7:
ΔABC is a right angled triangle , right angled at c .

Type: Long Difficulty: Easy
<p>Here, AB = 13 cm </p>
<p> AC = 5 cm </p>
<p> BC = ?</p>
<p>We know, in right angled ΔABC ,</p>
<p> h<sup>2</sup> = p<sup>2</sup> + b<sup>2</sup></p>
<p>or, ( AB )<sup>2</sup>= ( AC )<sup>2</sup> + ( BC )<sup>2</sup></p>
<p>or, ( 13 cm )<sup>2</sup>= (5 cm)<sup>2</sup> + ( BC )<sup>2</sup></p>
<p>or, 169 cm<sup>2 </sup>= 25 cm<sup>2</sup> +( BC )<sup>2</sup></p>
<p>or, 169 cm<sup>2 </sup>= 25 cm<sup>2</sup> + ( BC )<sup>2</sup></p>
<p>or, 169 cm<sup>2 </sup>- 25 cm<sup>2</sup> = ( BC )<sup>2</sup></p>
<p>or, 144 cm <sup>2</sup>= ( BC )<sup>2</sup></p>
<p>or, ( BC )<sup>2</sup> = 144 cm <sup>2</sup></p>
<p>or, ( BC )<sup>2 </sup>= ( 12 cm )<sup>2</sup></p>
<p>∴ BC = 12 cm </p>
<p>Hence, the unknown side BC = 12 cm.</p>
Q8:
Here, MNO is a right angled triangle, right angled at N. Find MO = ?

Type: Long Difficulty: Easy
<p>So, MN = 1 cm </p>
<p> NO = 1 cm</p>
<p> MO = ?</p>
<p>We know , </p>
<p>or, h<sup>2 </sup>= p<sup>2</sup> + b<sup>2</sup> (Since, MNO is a right angled triangle )</p>
<p>or, ( MO )<sup>2</sup>= ( MN )<sup>2</sup> + ( NO )<sup>2</sup></p>
<p>or, ( MO )<sup>2</sup>= (1 cm )<sup>2</sup>+ ( 1 cm )<sup>2</sup></p>
<p>or, ( MO )<sup>2</sup>= 1 cm + 1 cm</p>
<p>or, ( MO )<sup>2</sup>= 2cm</p>
<p><sup> </sup>∴ MO = \(\sqrt{2}\) cm </p>
<p>Hence, the reqired side, MO = \(\sqrt{2}\) cm .</p>
Q9:
Find p , b and h from the figures given below with the reference angles given .

Type: Short Difficulty: Easy
<p>Here, ΔABC is a right angled triangle right angled at A.</p>
<p>i.e. ∠BAC = 90 .</p>
<p>∠ACB = α ( reference angle )</p>
<p> ∴ Side AB = perpendicular ( p )</p>
<p> Side BC = Hypotenuse ( h )</p>
<p> Side AC =base ( b )</p>
Q10:
Determine whether the triangle is right angled triangle or not ?
1)

2)

Type: Long Difficulty: Easy
<p>Solution ;</p>
<p>Here, PT = 3 cm</p>
<p> PO = 2cm </p>
<p> OT = 2 cm </p>
<p>Now, for ΔPOT to be a right angled triangle , </p>
<p> h<sup>2</sup> = p <sup>2</sup>+ b<sup>2</sup></p>
<p>or, ( PT )<sup>2</sup>= ( PO )<sup>2</sup> + ( TO )<sup>2</sup> ( PT is the longest side )</p>
<p>or, ( 3 cm )<sup>2 </sup>= ( 2 cm )<sup>2</sup>+ ( 2 cm )<sup>2</sup></p>
<p>or, 9 cm<sup>2</sup> = 4 cm<sup>2</sup> + 4 cm<sup>2</sup></p>
<p>or, 9 cm<sup>2 </sup>= 8 cm<sup>2</sup> ( which is false )</p>
<p>Hence, Δ POT is not a right angled triangle .</p>
<p> </p>
<p>2.</p>
<p>Solution :</p>
<p>Here, AU = 5 cm </p>
<p> US = 3 cm </p>
<p> SA = 4 cm </p>
<p>Now, for the ΔUSA to be a right angled triangle ,</p>
<p> h<sup>2</sup> = p<sup>2</sup> + b<sup>2</sup></p>
<p>As, AU = 5 cm, lets consider it to be the hypotenuse.</p>
<p>[\(\therefore\) The longest side is the hypotenuse]</p>
<p>Now, (UA)<sup>2</sup> = (US)<sup>2</sup> + (SA)<sup>2</sup></p>
<p>(5 cm)<sup>2</sup> = (3 cm)<sup>2</sup> + (4 cm)<sup>2</sup></p>
<p>25 cm<sup>2</sup> = 9cm<sup>2</sup> +16 cm<sup>2</sup></p>
<p>25 cm<sup>2</sup> = 25 cm<sup>2</sup> which is true.</p>
<p>Hence, \(\triangle\)USA is a right angled triangle.</p>
Q11:
The figure is Δ ABC right angled triangle. Find sinθ and cos∝.

Here p= 3cm, b = 4 cm
Type: Long Difficulty: Easy
<p>Here, in the right-angled Δ ABC, ACD = 90</p>
<p>So, h<sup>2</sup> = P<sup>2</sup> + b<sup>2</sup></p>
<p> (AB)<sup>2</sup> = (AC)<sup>2</sup> + (BC)<sup>2</sup> </p>
<p> (AB)<sup>2</sup> = (3cm)<sup>2</sup> + (4 cm)<sup>2</sup></p>
<p> (AB)<sup>2</sup> = 9 cm<sup>2</sup> + 16 cm<sup>2</sup></p>
<p><sup> </sup>(AB)<sup>2</sup> = 25 cm<sup>2</sup></p>
<p><sup> </sup>(AB0 = 5 cm</p>
<p>Now, taking θ as the reference angle,</p>
<p>sinθ = \(\frac{p}{h}\)</p>
<p> = \(\frac{BC}{AB}\) = \(\frac{3}{4}\)</p>
<p>Again, takiing ∝ as the reference angle,</p>
<p>cos∝ = \(\frac{b}[h}\) = \(\frac{BC}{AB}\) = \(\frac{3}{4}\)</p>
<p> </p>
<p> </p>
<p> </p>
<p> </p>
<p> </p>
Q12:
What is a Pythagoras Theorem?
Type: Short Difficulty: Easy
Q13:
Find p , b and h from the figures given below with the reference angles given.

Type: Short Difficulty: Easy
<p>Here, ΔQRS is a right angled triangle right angled at R.</p>
<p>i.e. ∠QRS = 90 .</p>
<p>∠QSR = α ( reference angle )</p>
<p> ∴ Side QR = perpendicular ( p ) </p>
<p> Side QS = Hypotenuse ( h )</p>
<p> Side SR =base ( b )</p>
<p>Again, </p>
<p>we know that, </p>
<p>h<sup>2</sup> = p<sup>2</sup> + b<sup>2 </sup></p>
<p>h<sup>2</sup> = (3 cm)<sup>2 </sup>+ (4 cm)<sup>2</sup> </p>
<p>h<sup>2</sup> = 9 cm + 12 cm </p>
<p>h<sup>2</sup> = 25 cm</p>
<p>h<sup>2</sup> = (5 cm)<sup>2</sup> </p>
<p>h = 5</p>
Q14:
The figure is Δ ABC right angled triangle. Find sinθ and cos∝.

Here p= 5cm, b = 12 cm
Type: Short Difficulty: Easy
<p>Here, in the right-angled Δ ABC = 90</p>
<p>So, h<sup>2</sup> = P<sup>2</sup> + b<sup>2</sup></p>
<p> (AB)<sup>2</sup> = (AC)<sup>2</sup> + (BC)<sup>2</sup> </p>
<p> (AB)<sup>2</sup> = (5cm)<sup>2</sup> + (12 cm)<sup>2</sup></p>
<p> (AB)<sup>2</sup> = 25 cm<sup>2</sup> + 144 cm<sup>2</sup></p>
<p><sup> </sup>(AB)<sup>2</sup> = 169 cm<sup>2</sup></p>
<p><sup> </sup>AB = 13 cm</p>
<p>Now, taking θ as the reference angle,</p>
<p>sinθ = \(\frac{p}{h}\)</p>
<p> = \(\frac{BC}{AB}\) = \(\frac{3}{4}\)</p>
<p>Again, takiing ∝ as the reference angle,</p>
<p>cos∝ = \(\frac{b}{h}\) <br /> = \(\frac{BC}{AB}\) = \(\frac{3}{4}\)</p>
<p> </p>
<p> </p>
<p> </p>
<p> </p>
<p> </p>
Q15:
The figure is Δ ABC right angled triangle. Find sinθ and cos∝.
Here p= 5cm, b = 12 cm
Type: Short Difficulty: Easy
<p>Here, in the right-angled Δ ABC = 90</p>
<p>So, h<sup>2</sup> = P<sup>2</sup> + b<sup>2</sup></p>
<p> (AB)<sup>2</sup> = (AC)<sup>2</sup> + (BC)<sup>2</sup> </p>
<p> (AB)<sup>2</sup> = (25cm)<sup>2</sup> + (12 cm)<sup>2</sup></p>
<p> (AB)<sup>2</sup> = 25 cm<sup>2</sup> + 144 cm<sup>2</sup></p>
<p><sup> </sup>(AB)<sup>2</sup> = 169 cm<sup>2</sup></p>
<p><sup> </sup>(AB)<sup>2</sup> = (13 cm)<sup>2</sup></p>
<p><sup> </sup>AB = 13 cm.</p>
<p> </p>
Q16:
The figure is Δ ABC right angled triangle.
Here p= 5cm, b = 12 cm
Type: Short Difficulty: Easy
<p>Here, in the right-angled Δ ABC = 90</p>
<p>So, h<sup>2</sup> = P<sup>2</sup> + b<sup>2</sup></p>
<p> (AB)<sup>2</sup> = (AC)<sup>2</sup> + (BC)<sup>2</sup> </p>
<p> (AB)<sup>2</sup> = (25cm)<sup>2</sup> + (12 cm)<sup>2</sup></p>
<p> (AB)<sup>2</sup> = 25 cm<sup>2</sup> + 144 cm<sup>2</sup></p>
<p><sup> </sup>(AB)<sup>2</sup> = 169 cm<sup>2</sup></p>
<p><sup> </sup>(AB)<sup>2</sup> = (13 cm)<sup>2</sup></p>
<p><sup> </sup>AB = 13 cm.</p>
<p> </p>
Q17:
Here, ABC is a right angled triangle , right angled at A.

AB = 2 cm
BC = 2cm
AC = ?
Type: Short Difficulty: Easy
<p>We know ,</p>
<p>h<sup>2</sup> = p<sup>2 </sup> + b<sup>2</sup>( Since ΔABC is a right angled triangle)</p>
<p>(AB)<sup>2</sup> = (AB)<sup>2</sup> + (BC)<sup>2</sup></p>
<p>(AB)<sup>2</sup> = (2cm)<sup>2</sup> + (2cm)<sup>2</sup></p>
<p>(AB)<sup>2</sup> = 4cm<sup>2</sup></p>
<p>AB = 4 cm ans.</p>
<p> </p>
Videos
Types of Triangles Based on Sides - Equilateral, Isosceles, Scalene
right angled triangle, given one side and one acute angle
Construction of an Acute Triangle
Construction of an Obtuse Triangle
Reference angle

Nutrition And Digestive Organs
Nutrition
all living organisms ned matter to build up the body and energy to operate the metabolic reaction that sustain life .
the material which provde these 2 primary requirement of life are called nutrients or food. The sum of the process by which the living organism obtain matter and energy is treamed nutriention
animal such as rabiits that subsist entire on plant material are called hervbivores . So there are nutrition of 2 types-
A autotropic nurtion
- all green plants and certain protists have evolved a meachnism to directly use the nergy of sunlight for preparing organic materials. This process of making food is called photosynthesis and the organism capable of its termed is called phototrophs
B Heterotropic nutrition
- animals fungi some prostists and many bacteria cann’t utilize sun energy . they use chemical bound – enery .they use chemical bound energy of organism molecules synthezied by other molecules such a mode of feeding is called heterotropic Nutrition
C heterotriphic Nutrition
- Saprotrophic nutrition – many organism absorb fluid food through their body surface . this is called saprotrophic nutrition the enzyme hydrolyzed the organism matter into simple soluble product that are then absorbed this method of up take is called saprotropic nutrition
- holotropic nutrition – majority of invertebrates and all vertebrates take plant , animal or their product through the mouth and break up the large organism molecules into smaller ones in their own body with the help of enzymes .this mode of taking food intake is called holotropic nutrition
here nutrition are further divided into 2 types
- macro nutrition
- micro nutrition
macro nutrition -
with few notable exceptions heterotrrophs requires organic molecules , such as carbohydrates, lipids na dproteins when these molecules are broken down by enzymes into components they can ebe form a energy and are know as the building block elements for the body
- micro nutritionas -
they are usually small ions Vitamins , inorganic mineral and molecules that are used over and over proteins
Deficiency of nutrition
it may lead to
malnutrition, kwashiorkor, marasmus and for pregnant women leads to featal death
Digestive organs
Digestion is simple the intake of food which would be further broken down in smaller particles helping for proper absorption of nurtitions.The process starts from the-
Oral Cavity , teeth, tongue
- as we take food there is an enzyme named alfa- salivary lipas which helps in digestion of food. Partcials into some extent.and in oral cavity there is presence of sliva as well which mixed food and makes it properly to swallow.
Salivary glands – secretion of lubricating fluid containg eneymes also help in break down of carbohydrates
Pharynx- in pharynx muscle popel material into esophagus
Esophagus- it Helps in transport of material to the stomach
Stomach – chemical breakdown of materials via acid and enzymes , mechanical process through muscular contration
Liver – Secretion of bile for lipid digestion , storage of nutrients , takes place
Gallbladder- storage and concentration of bile helping in digestion of food
Pancreas – Exocrine cell secrete buffer and digestive enzymes , endocrine cells secrete hormones
Small intestine – Enzymatic digestion and absorption of water organic substance , vit and ions
large intestine – Dehydration and compaction of indigestible material in preparation for elimination
fig Digestive organs
Lesson
Human Biology and Health
Subject
Biology
Grade
Grade 12
Recent Notes
No recent notes.
Related Notes
No related notes.