Nutrition And Digestive Organs

introduction to nutrition and their types along with their function and uses in our daily life

Summary

introduction to nutrition and their types along with their function and uses in our daily life

Things to Remember

Nutrition 
A autotropic nurtion
B Heterotropic nutrition 
C heterotriphic Nutrition 
macro nutrition -
Deficiency of nutrition
Oral Cavity , teeth, tongue 
Digestive organs 

MCQs

No MCQs found.

Subjective Questions

Q1:

Define triangle?


Type: Very_short Difficulty: Easy

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Answer: <p>A triangle is a geometrically closed figure which is bounded by three lines and angles .It is divided into two types they are sides and angles.</p>

Q2:

What is a reference angle ?


Type: Very_short Difficulty: Easy

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Answer: <p>A right-angled triangle which is taken into consideration is known as the reference angle</p>

Q3:

What is hypotenuse ?


Type: Very_short Difficulty: Easy

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Answer: <p>The side opposite to &nbsp;right angle is known as hypotenuse .</p>

Q4:

What is perpendicular ?


Type: Very_short Difficulty: Easy

Show/Hide Answer
Answer: <p>The side opposite to reference angle is known as perpendicular.</p>

Q5:

What is a base ?


Type: Very_short Difficulty: Easy

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Answer: <p>The side except hypotenuse &nbsp;and the perpendicular is called base .</p>

Q6:

Find the unknown  side from the given right angled triangles .

s 

Type: Long Difficulty: Easy

Show/Hide Answer
Answer: <p>Solution;</p>
<p>Let, PQR be a right angled triangle where&nbsp;right angled at Q .</p>
<p>So, &nbsp; &nbsp;PQ = 3 cm&nbsp;</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;QR = 4 cm&nbsp;</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; PR = ?</p>
<p>We know, in right angled PQR ,</p>
<p>&nbsp;h<sup>2&nbsp;</sup>= p<sup>2&nbsp;</sup>+ b<sup>2</sup></p>
<p>so,( PR )<sup>2</sup>= ( PQ )<sup>2</sup> + ( QR )<sup>2</sup></p>
<p>(PR)<sup>2</sup> = (3cm)<sup>2</sup> + (4cm)<sup>2 &nbsp;</sup></p>
<p>(PR)<sup>2</sup> = 9 cm + 12 cm</p>
<p>(PR)<sup>2</sup> = 25 cm<sup>2</sup></p>
<p>or, (PR )<sup>2</sup>= ( 5cm )<sup>2</sup></p>
<p>&there4; PR = 5 cm .</p>
<p>Hence , the unknown side PR = 5 cm .</p>

Q7:

ΔABC is a right angled triangle , right angled at c .

s

Type: Long Difficulty: Easy

Show/Hide Answer
Answer: <p>Solution ;</p>
<p>Here, AB = 13 cm&nbsp;</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; AC = 5 cm&nbsp;</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; BC = ?</p>
<p>We know, &nbsp;in right angled&nbsp;&Delta;ABC ,</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; h<sup>2</sup> = p<sup>2</sup> + b<sup>2</sup></p>
<p>or, ( AB )<sup>2</sup>= ( AC )<sup>2</sup> + ( BC )<sup>2</sup></p>
<p>or, ( 13 cm )<sup>2</sup>= (5 cm)<sup>2</sup> + ( BC )<sup>2</sup></p>
<p>or, 169 cm<sup>2&nbsp;</sup>= 25 cm<sup>2</sup> +( BC )<sup>2</sup></p>
<p>or, 169 cm<sup>2&nbsp;</sup>= 25 cm<sup>2</sup>&nbsp;+ ( BC )<sup>2</sup></p>
<p>or, 169 cm<sup>2 &nbsp;</sup>-&nbsp;25 cm<sup>2</sup>&nbsp; = ( BC )<sup>2</sup></p>
<p>or, 144 cm&nbsp;<sup>2</sup>= ( BC )<sup>2</sup></p>
<p>or, ( BC )<sup>2</sup> = 144 cm&nbsp;<sup>2</sup></p>
<p>or, ( BC )<sup>2&nbsp;</sup>= ( 12 cm )<sup>2</sup></p>
<p>&there4; BC = 12 cm &nbsp;</p>
<p>Hence, the unknown side BC = 12 cm.</p>

Q8:

Here, MNO is  a right angled triangle, right angled at N. Find MO = ?

 

s

Type: Long Difficulty: Easy

Show/Hide Answer
Answer: <p>Solution :</p>
<p>So, MN = 1 cm&nbsp;</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;NO = 1 cm</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;MO = ?</p>
<p>We know ,&nbsp;</p>
<p>or, h<sup>2&nbsp;</sup>= p<sup>2</sup> + b<sup>2</sup>&nbsp;(Since, MNO is a right angled triangle )</p>
<p>or, ( MO )<sup>2</sup>= ( MN )<sup>2</sup> + ( NO )<sup>2</sup></p>
<p>or, ( MO )<sup>2</sup>= (1 cm )<sup>2</sup>+ ( 1 cm )<sup>2</sup></p>
<p>or, ( MO )<sup>2</sup>= 1 cm + 1 cm</p>
<p>or, ( MO )<sup>2</sup>=&nbsp;2cm</p>
<p><sup>&nbsp;</sup>&there4; MO = \(\sqrt{2}\) cm&nbsp;</p>
<p>Hence, the reqired side, MO = \(\sqrt{2}\) cm .</p>

Q9:

Find p , b and h from the figures given below with the reference angles given .

s

 


Type: Short Difficulty: Easy

Show/Hide Answer
Answer: <p>Solution ;</p>
<p>Here,&nbsp;&Delta;ABC is a right angled triangle &nbsp;right angled at A.</p>
<p>i.e.&nbsp;&ang;BAC = 90 .</p>
<p>&ang;ACB =&nbsp;&alpha; ( reference angle )</p>
<p>&nbsp;&there4; Side AB = perpendicular ( p )</p>
<p>&nbsp; &nbsp; &nbsp;Side BC = Hypotenuse ( h )</p>
<p>&nbsp; &nbsp; &nbsp;Side AC =base &nbsp;( b )</p>

Q10:

Determine whether the triangle is right angled triangle or not ?

1)

s

 

2)

s

Type: Long Difficulty: Easy

Show/Hide Answer
Answer: <p>1 .</p>
<p>Solution ;</p>
<p>Here,&nbsp;PT = 3 cm</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;PO = 2cm&nbsp;</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;OT = 2 cm&nbsp;</p>
<p>Now, for&nbsp;&Delta;POT to be a right angled triangle ,&nbsp;</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; h<sup>2</sup> = p <sup>2</sup>+ b<sup>2</sup></p>
<p>or, ( PT )<sup>2</sup>= ( PO )<sup>2</sup> + ( TO )<sup>2</sup>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;( PT is the longest side )</p>
<p>or, ( 3 cm )<sup>2&nbsp;</sup>= ( 2 cm )<sup>2</sup>+ ( 2 cm )<sup>2</sup></p>
<p>or, &nbsp; &nbsp; 9 cm<sup>2</sup> = 4 cm<sup>2</sup> + 4 cm<sup>2</sup></p>
<p>or, &nbsp; &nbsp; 9 cm<sup>2&nbsp;</sup>= 8 cm<sup>2</sup> ( which is false )</p>
<p>Hence,&nbsp;&Delta; POT is not a right angled &nbsp;triangle .</p>
<p>&nbsp;</p>
<p>2.</p>
<p>Solution :</p>
<p>Here,&nbsp;AU = 5 cm&nbsp;</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; US = 3 cm&nbsp;</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; SA = 4 cm&nbsp;</p>
<p>Now, for the&nbsp;&Delta;USA to be a right angled triangle ,</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;h<sup>2</sup>&nbsp;= p<sup>2</sup> + b<sup>2</sup></p>
<p>As, AU = 5 cm, lets consider it to be the hypotenuse.</p>
<p>[\(\therefore\) The longest side is the hypotenuse]</p>
<p>Now, (UA)<sup>2</sup> = (US)<sup>2</sup> + (SA)<sup>2</sup></p>
<p>(5 cm)<sup>2</sup> = (3 cm)<sup>2</sup> + (4 cm)<sup>2</sup></p>
<p>25 cm<sup>2</sup> = 9cm<sup>2</sup> +16 cm<sup>2</sup></p>
<p>25 cm<sup>2</sup> = 25 cm<sup>2</sup> which is true.</p>
<p>Hence, \(\triangle\)USA is a right angled triangle.</p>

Q11:

The figure is Δ ABC right angled triangle. Find sinθ and cos∝.

s

Here p= 3cm, b = 4 cm


Type: Long Difficulty: Easy

Show/Hide Answer
Answer: <p>Solution</p>
<p>Here, in the right-angled&nbsp;&Delta; ABC, ACD = 90</p>
<p>So, h<sup>2</sup> = &nbsp;P<sup>2</sup> + b<sup>2</sup></p>
<p>&nbsp; &nbsp;(AB)<sup>2</sup> = (AC)<sup>2</sup> + (BC)<sup>2</sup>&nbsp;&nbsp;</p>
<p>&nbsp; &nbsp;(AB)<sup>2</sup> = (3cm)<sup>2</sup> + (4 cm)<sup>2</sup></p>
<p>&nbsp; &nbsp;(AB)<sup>2</sup> = 9 cm<sup>2</sup> + 16 cm<sup>2</sup></p>
<p><sup>&nbsp; &nbsp;</sup>(AB)<sup>2</sup> = 25 cm<sup>2</sup></p>
<p><sup>&nbsp;&nbsp;</sup>(AB0 = 5 cm</p>
<p>Now, taking&nbsp;&theta; as the reference angle,</p>
<p>sin&theta; = \(\frac{p}{h}\)</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = \(\frac{BC}{AB}\) = \(\frac{3}{4}\)</p>
<p>Again, takiing&nbsp;&prop; as the reference angle,</p>
<p>cos&prop; = \(\frac{b}[h}\) = \(\frac{BC}{AB}\) = \(\frac{3}{4}\)</p>
<p>&nbsp;</p>
<p>&nbsp;</p>
<p>&nbsp;&nbsp;</p>
<p>&nbsp;</p>
<p>&nbsp;</p>

Q12:

What is a Pythagoras Theorem?


Type: Short Difficulty: Easy

Show/Hide Answer
Answer: <p>Pythagoras Theorem is a relation developed on the basis of the elements of right angled triangle. It is established by a famous &nbsp;mathematician named Pythagoras. &nbsp;The elements of a right-angled triangle &nbsp;are perpendicular, base and hypotenuse.&nbsp;</p>

Q13:

Find p , b and h from the figures given below with the reference angles given.

s

 


Type: Short Difficulty: Easy

Show/Hide Answer
Answer: <p>Solution ;</p>
<p>Here,&nbsp;&Delta;QRS is a right angled triangle &nbsp;right angled at R.</p>
<p>i.e.&nbsp;&ang;QRS = 90 .</p>
<p>&ang;QSR =&nbsp;&alpha; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;( reference angle )</p>
<p>&nbsp;&there4; Side QR = perpendicular ( p )&nbsp;</p>
<p>&nbsp; &nbsp; &nbsp;Side QS = Hypotenuse ( h )</p>
<p>&nbsp; &nbsp; &nbsp;Side SR =base &nbsp;( b )</p>
<p>Again,&nbsp;</p>
<p>we know that,&nbsp;</p>
<p>h<sup>2</sup> &nbsp;= p<sup>2</sup> + b<sup>2&nbsp;</sup></p>
<p>h<sup>2</sup> = (3 cm)<sup>2&nbsp;</sup>+ (4 cm)<sup>2</sup>&nbsp;</p>
<p>h<sup>2</sup> = 9 cm + 12 cm&nbsp;</p>
<p>h<sup>2</sup> = 25 cm</p>
<p>h<sup>2</sup> = (5 cm)<sup>2</sup>&nbsp;</p>
<p>h = 5</p>

Q14:

The figure is Δ ABC right angled triangle. Find sinθ and cos∝.

s

Here p= 5cm, b = 12 cm


Type: Short Difficulty: Easy

Show/Hide Answer
Answer: <p>Solution</p>
<p>Here, in the right-angled&nbsp;&Delta; ABC = 90</p>
<p>So, h<sup>2</sup> = &nbsp;P<sup>2</sup> + b<sup>2</sup></p>
<p>&nbsp; &nbsp;(AB)<sup>2</sup> = (AC)<sup>2</sup> + (BC)<sup>2</sup>&nbsp;&nbsp;</p>
<p>&nbsp; &nbsp;(AB)<sup>2</sup> = (5cm)<sup>2</sup> + (12 cm)<sup>2</sup></p>
<p>&nbsp; &nbsp;(AB)<sup>2</sup> = 25 cm<sup>2</sup> + 144 cm<sup>2</sup></p>
<p><sup>&nbsp; &nbsp;</sup>(AB)<sup>2</sup> = 169 cm<sup>2</sup></p>
<p><sup>&nbsp;&nbsp;</sup>AB = 13 cm</p>
<p>Now, taking&nbsp;&theta; as the reference angle,</p>
<p>sin&theta; = \(\frac{p}{h}\)</p>
<p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = \(\frac{BC}{AB}\) = \(\frac{3}{4}\)</p>
<p>Again, takiing&nbsp;&prop; as the reference angle,</p>
<p>cos&prop; = \(\frac{b}{h}\) <br />&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= \(\frac{BC}{AB}\) = \(\frac{3}{4}\)</p>
<p>&nbsp;</p>
<p>&nbsp;</p>
<p>&nbsp;&nbsp;</p>
<p>&nbsp;</p>
<p>&nbsp;</p>

Q15:

The figure is Δ ABC right angled triangle. Find sinθ and cos∝. 

Here p= 5cm, b = 12 cm


Type: Short Difficulty: Easy

Show/Hide Answer
Answer: <p>Solution</p>
<p>Here, in the right-angled&nbsp;&Delta; ABC = 90</p>
<p>So, h<sup>2</sup> = &nbsp;P<sup>2</sup> + b<sup>2</sup></p>
<p>&nbsp; &nbsp;(AB)<sup>2</sup> = (AC)<sup>2</sup> + (BC)<sup>2</sup>&nbsp;&nbsp;</p>
<p>&nbsp; &nbsp;(AB)<sup>2</sup> = (25cm)<sup>2</sup> + (12 cm)<sup>2</sup></p>
<p>&nbsp; &nbsp;(AB)<sup>2</sup> = 25 cm<sup>2</sup> + 144 cm<sup>2</sup></p>
<p><sup>&nbsp; &nbsp;</sup>(AB)<sup>2</sup> = 169 cm<sup>2</sup></p>
<p><sup>&nbsp;&nbsp;</sup>(AB)<sup>2</sup> = (13 cm)<sup>2</sup></p>
<p><sup>&nbsp;&nbsp;</sup>AB = 13 cm.</p>
<p>&nbsp;</p>

Q16:

The figure is Δ ABC right angled triangle. 

Here p= 5cm, b = 12 cm


Type: Short Difficulty: Easy

Show/Hide Answer
Answer: <p>Solution</p>
<p>Here, in the right-angled&nbsp;&Delta; ABC = 90</p>
<p>So, h<sup>2</sup> = &nbsp;P<sup>2</sup> + b<sup>2</sup></p>
<p>&nbsp; &nbsp;(AB)<sup>2</sup> = (AC)<sup>2</sup> + (BC)<sup>2</sup>&nbsp;&nbsp;</p>
<p>&nbsp; &nbsp;(AB)<sup>2</sup> = (25cm)<sup>2</sup> + (12 cm)<sup>2</sup></p>
<p>&nbsp; &nbsp;(AB)<sup>2</sup> = 25 cm<sup>2</sup> + 144 cm<sup>2</sup></p>
<p><sup>&nbsp; &nbsp;</sup>(AB)<sup>2</sup> = 169 cm<sup>2</sup></p>
<p><sup>&nbsp;&nbsp;</sup>(AB)<sup>2</sup> = (13 cm)<sup>2</sup></p>
<p><sup>&nbsp;&nbsp;</sup>AB = 13 cm.</p>
<p>&nbsp;</p>

Q17:

Here, ABC is a right angled triangle , right angled at A.

s

AB = 2 cm 

BC = 2cm

AC = ?

 


Type: Short Difficulty: Easy

Show/Hide Answer
Answer: <p>Solution</p>
<p>We know ,</p>
<p>h<sup>2</sup> = p<sup>2&nbsp;</sup> + b<sup>2</sup>( Since&nbsp;&Delta;ABC is a right angled triangle)</p>
<p>(AB)<sup>2</sup> = (AB)<sup>2</sup> + (BC)<sup>2</sup></p>
<p>(AB)<sup>2</sup> = (2cm)<sup>2</sup> + (2cm)<sup>2</sup></p>
<p>(AB)<sup>2</sup> &nbsp;= &nbsp;4cm<sup>2</sup></p>
<p>AB = 4 cm ans.</p>
<p>&nbsp;</p>

Videos

Types of Triangles Based on Sides - Equilateral, Isosceles, Scalene
right angled triangle, given one side and one acute angle
Construction of an Acute Triangle
Construction of an Obtuse Triangle
Reference angle
Nutrition And Digestive Organs

Nutrition And Digestive Organs

Nutrition
all living organisms ned matter to build up the body and energy to operate the metabolic reaction that sustain life .
the material which provde these 2 primary requirement of life are called nutrients or food. The sum of the process by which the living organism obtain matter and energy is treamed nutriention
animal such as rabiits that subsist entire on plant material are called hervbivores . So there are nutrition of 2 types-
A autotropic nurtion
- all green plants and certain protists have evolved a meachnism to directly use the nergy of sunlight for preparing organic materials. This process of making food is called photosynthesis and the organism capable of its termed is called phototrophs
B Heterotropic nutrition
- animals fungi some prostists and many bacteria cann’t utilize sun energy . they use chemical bound – enery .they use chemical bound energy of organism molecules synthezied by other molecules such a mode of feeding is called heterotropic Nutrition
C heterotriphic Nutrition
- Saprotrophic nutrition – many organism absorb fluid food through their body surface . this is called saprotrophic nutrition the enzyme hydrolyzed the organism matter into simple soluble product that are then absorbed this method of up take is called saprotropic nutrition
- holotropic nutrition – majority of invertebrates and all vertebrates take plant , animal or their product through the mouth and break up the large organism molecules into smaller ones in their own body with the help of enzymes .this mode of taking food intake is called holotropic nutrition
here nutrition are further divided into 2 types
- macro nutrition
- micro nutrition

macro nutrition -
with few notable exceptions heterotrrophs requires organic molecules , such as carbohydrates, lipids na dproteins when these molecules are broken down by enzymes into components they can ebe form a energy and are know as the building block elements for the body
- micro nutritionas -
they are usually small ions Vitamins , inorganic mineral and molecules that are used over and over proteins
Deficiency of nutrition
it may lead to
malnutrition, kwashiorkor, marasmus and for pregnant women leads to featal death



Digestive organs



Digestion is simple the intake of food which would be further broken down in smaller particles helping for proper absorption of nurtitions.The process starts from the-
Oral Cavity , teeth, tongue
- as we take food there is an enzyme named alfa- salivary lipas which helps in digestion of food. Partcials into some extent.and in oral cavity there is presence of sliva as well which mixed food and makes it properly to swallow.
Salivary glands – secretion of lubricating fluid containg eneymes also help in break down of carbohydrates
Pharynx- in pharynx muscle popel material into esophagus
Esophagus- it Helps in transport of material to the stomach
Stomach – chemical breakdown of materials via acid and enzymes , mechanical process through muscular contration
Liver – Secretion of bile for lipid digestion , storage of nutrients , takes place
Gallbladder- storage and concentration of bile helping in digestion of food
Pancreas – Exocrine cell secrete buffer and digestive enzymes , endocrine cells secrete hormones
Small intestine – Enzymatic digestion and absorption of water organic substance , vit and ions
large intestine – Dehydration and compaction of indigestible material in preparation for elimination




fig Digestive organs

Lesson

Human Biology and Health

Subject

Biology

Grade

Grade 12

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